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ivann1987 [24]
3 years ago
15

Deshawn is filling out online applications for summer jobs. So far, he has filled out 7applications. Fiona has filled out 3 time

s as many applications as Deshawn. How many more applications has Fiona completed than Deshawn? Which best shows whether or not 14 is a reasonable answer? It is reasonable because 7 × 3 – 7 = 14. It is reasonable because 7 + 3 + 7 = 17. It is not reasonable because 7 + 3 – 7 = 3. It is not reasonable because 7 × 3 + 7 = 28
Mathematics
2 answers:
olga2289 [7]3 years ago
6 0
The answer is 14, so 7x3-7=14 is correct.
Ludmilka [50]3 years ago
5 0
The answer would be It is reasonable because
7 \times 3 - 7 = 14


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Martina buys a video game that normally costs d dollars, but it is on sale for 25% off. If the sales tax on the game is 8%, how
NNADVOKAT [17]

25% off means that they are paying 75% of the original price. Multiply d by 75%:

0.75d

Now you need to multiply the price by 1 plus the sales tax to get the total cost:

0.75d x 1.08

Simplify by multiplying 0.75 by 1.08 to get:

0.81d

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you have a work meeting that starts at 1:15 pm. you arrived at 12:53 pm. how many minutes early were you?
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3 0
3 years ago
Solve for x. 3x/2 = 15
defon

3x : 2 = 15

3x = 15 * 2

3x = 30

x = 30 : 3

x = 10

--------------------------------

3(10)  :2 = 15

6 0
3 years ago
Lindsay draws a right triangle and adds the measures of the right angle and one acute angle. Which is a possible sum of the two
Anon25 [30]
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6 0
3 years ago
Read 2 more answers
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts
kirill115 [55]

Answer:

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666    

p_v =2*P(Z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.5 represent the sample mean

\sigma=1.1 represent the population standard deviation

n=860 sample size  

\mu_o =4.6 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:  

Null hypothesis:\mu = 4.6  

Alternative hypothesis:\mu \neq 4.6  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666  

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

5 0
3 years ago
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