The diagram shows four different locations in an atom.
2 answers:
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<h3>Answer:</h3>
251 mol Xe
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[Given] 1.51 × 10²⁶ atoms Xe
[Solve] moles Xe
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rule and round. We are given 3 sig figs.</em>
250.747 mol Xe ≈ 251 mol Xe
Answer:
Explanation:
This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.
It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.
If heat flows out of the reactor (negative), the same amount of heat must flow into the water (positive).
Since there is no change in total energy,
heat₁ + heat₂ = 0
The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as
q₁ + q₂ = 0
The formula for the heat absorbed or released by an object is
q = mCΔT, where
m = the mass of the sample
C = the specific heat capacity of the sample, and
ΔT = T_f - T_i = the change in temperature
1. Equation
There are two heat flows in this problem,
heat released by reactor + heat absorbed by water = 0
q₁ + q₂ = 0
q₁ + m₂C₂ΔT₂ = 0
2. Data:
q₁ = -23 746 kJ
m₂ = ?; C₂ = 4.184 J°C⁻¹g⁻¹; T_f = 95 °C; T_i = 10 °C
3. Calculations
(a) Convert kilojoules to joules
(b) ΔT
ΔT₂ = T_f - T_i = 95 °C - 10 °C = 85 °C
(c) m₂