Total mass of CaCO3 = 40 amu of Ca + 12amu of C + 16×3 amu of oxygen = 100amu of CaCO3
i.e 100 tonnes of CaCO3 .
mass of CO2 = 12amu of C + 2× 16amu of O = 44 amu of CO2
mass % of CO2 in CaCO3 = (44/100)×100 =44%
i.e
44% of 100 tonnes is CO2.
=44 tonnes of CO2.
therefore, 44% of CO2 is present in CaCO3.
No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.
Answer: -
The mechanism for Br production from NBS is shown in the attached file.
N-bromo succinimide is a reagent used to brominate. It is most commonly used in allylic bromination, where a hydrogen on a carbon adjacent to a double bond is replaced.
It is selective in nature, unaffecting the normal double bond as compared to only bromine.
It also has a low concentration of bromine as an added advantage.
Answer:
4.13 moles of Fe will be produced in the reaction
Explanation:
To produce Fe from CO, we need to react Fe₂O₃ and the carbon monoxide.
The reaction is:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
1 mol of iron (III) oxide react to 3 moles of carbon monoxide in order to produce 2 moles of Iron and 3 moles of carbon dioxide.
We assume, the Fe₂O₃ in excess, so we propose this rule of three
3 moles of CO can produce 2 moles of Fe
Therefore 6.20 moles of CO will produce (6.20 . 2)/3 = 4.13 moles of Fe
Answer: 176 g N2O, 72 g H2O
Explanation:
1. 64g O2 * (1 mol O2)/(32 g O2) * (2 mol N2O)/(1 mol O2) * (44g N2O)/(1 mol N2O) = 176 g N2O
2. 32g CH4 * ( 1 mol CH4)/(16 g CH4) * (2 mol H2O)/(1 mol CH4) * (18 g H2O)/(1 mol H2O) = 72 g H2O
