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lidiya [134]
2 years ago
14

Abdul drove 380 miles using 14 gallons of gas. At this rate, how many gallons of gas would he need to drive 418 miles?

Mathematics
1 answer:
Alex17521 [72]2 years ago
7 0

Answer:

<u>15.4 gallons</u>

Step-by-step explanation:

This can be solved using a proportion. Keep in mind that "mi." is miles and "g" is gallons

\frac{14g}{380mi}=\frac{g}{418}

Cross multiply.

380g = 5852

Solve.

\frac{380g}{380}=\frac{5852}{380}  \\\\g = 15.4

Therefore, Adbul would need 15.4 gallons to drive 418 miles.


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Determine the equation of a line that passrs through the point (4,-1) and also parallel to y=3x+4
nexus9112 [7]
First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).

-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b

Now, put your m and b into y=mx+b.

The final answer/equation of your line is:

y=3x -13
5 0
3 years ago
0.1325 to thr hundredths
viktelen [127]
.13 hope this helps :D
6 0
3 years ago
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Se tiene la sucesión 3, 8, 13, 18, 23 … ¿Cuáles son los siguientes dos términos y cuál es la regla general?
V125BC [204]

Respuesta:

28; 33

A (n) = 5n - 2

Explicación paso a paso:

A partir de los datos dados, 3, 8, 13, 18, 23…, podemos ver que cada valor sucesivo de la serie aumenta en 5;

Por lo tanto, los siguientes dos términos de la serie deberían ser:

23 + 5 = 28

28 + 5 = 33

La serie es una progresión aritmética:

Recuerde la fórmula general:

A (norte) = a + (norte - 1) d

Donde, a = Primer término = 3; d = diferencia común = 5

n = enésimo término

A (n) = 3 + (n-1) 5

A (n) = 3 + 5n - 5

A (n) = 5n - 2

6 0
3 years ago
Write the percent as a fraction or mixed number in simplest form. <br> 62%
suter [353]
= 62%

= 0.62

= 62/100

= 31/50

6 0
3 years ago
Read 2 more answers
Simplify:<br> 5/4x-8y-1/4x+7y+3<br> A)x-y+3<br> B)3/2x+y+3<br> C)3/2x-y+3<br> D)x+y+3
Dovator [93]
<span>A)x-y+3 is your answer 

Proof:

(5 x)/4 - 8 y - x/4 + 7 y + 3
Put each term in (5 x)/4 - 8 y - x/4 + 7 y + 3 over the common denominator 4: (5 x)/4 - 8 y - x/4 + 7 y + 3 = (5 x)/4 - (32 y)/4 - (x)/4 + (28 y)/4 + 12/4:
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4 = (5 x - 32 y - x + 28 y + 12)/4:
(5 x - 32 y - x + 28 y + 12)/4
Grouping like terms, 5 x - 32 y - x + 28 y + 12 = (28 y - 32 y) + (5 x - x) + 12:
((28 y - 32 y) + (5 x - x) + 12)/4
28 y - 32 y = -4 y:
(-4 y + (5 x - x) + 12)/4
5 x - x = 4 x:
(-4 y + 4 x + 12)/4
Factor 4 out of -4 y + 4 x + 12:
(4 (-y + x + 3))/4
(4 (-y + x + 3))/4 = 4/4×(3 + x - y) = 3 + x - y:
Answer:  3 + x - y
</span>
6 0
3 years ago
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