I believe the answer is 8
Answer:
- x + y ≤ 600
- 5x +7y ≥ 3500
- it is possible
Step-by-step explanation:
a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.
x + y ≤ 600 . . . . . . . limit imposed by available seating
5x +7y ≥ 3500 . . . . required revenue to meet expenses
__
b) For x = 330, the first inequality puts one limit on y:
330 +y ≤ 600
y ≤ 270
And the second inequality puts another limit on y:
5(330) +7y ≥ 3500
7y ≥ 1850 . . . . subtract 1650
y ≥ 264.3 . . . . divide by 7
The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.
Max' brother is M-6 years old.
The answer is letter is C. 19.5 Because you divide
Answer:
log (16)=2 in base 3x-5
==>16=2^(3x-5)
==>2^4=2^(3x-5)
==>4=3x-5
==>3x=9
==>x=3
Step-by-step explanation:
