Question

Determine the percent Ammonia, NH3 in Co(NH3)6Cl3, to three significant figures.

Answer 1

Answer: Percent ammonia in  $Co(NH_3)_6Cl_3$ is 38.2 % in 3 significant figures.

Explanation:

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of ammonia}=\frac{\text{Mass of ammonia}}{\text{Molar mass of}Co(NH_3)_6Cl_3}\times 100$

Molar mass of $Co(NH_3)_6Cl_3$ = 267 g/mol

Mass of $NH_3$ = $6\times 17g/mol=102g$

Thus $\text{Mass percent of ammonia}}=\frac{102}{267}\times 100=38.2\%$

Thus percent ammonia in  $Co(NH_3)_6Cl_3$ is 38.2 % in 3 significant figures.