Answer:
The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.
Step-by-step explanation:
Central Limit Theorem:
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean 
and standard deviation 
75% of teenagers in North America are pursuing a goal they have set for themselves.
This means that 
Sample of 200.
This means that 
.
What are the mean and standard deviation of the sampling distribution of p?
By the Central Limit Theorem
Mean 
Standard deviation 
The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.
ANSWER:
V= 3,619.1 km^3
EXPLANATION:
Simply plug in the radius (12 km) and height (24 km) into the cone volume formula.
He might be 6 now.
hope this helped :)
plzz tell me if I was wrong
The question is incomplete:
James has dimes and quarters saved up in his change jar. He has a total of 162 coins totaling $31.20 what is the total amount james has in quarters?
a. $10.00
b. $6.20
c.$15.50
d.$25.00
Answer:
d.$25.00
Step-by-step explanation:
With the information provided, you can write the following equations given that dimes are equal to 0.10 and quarters to 0.25 to determine the number of dimes and quarters that James has:
x+y=162 (1)
0.10x+0.25y=31.20 (2), where:
x is the number of dimes
y is the number of quarters
First, you can solve for x in (1):
x=162-y (3)
Then, you have to replace (3) in (2) and solve for y:
0.10(162-y)+0.25y=31.20
16.2-0.10y+0.25y=31.20
0.15y=31.20-16.2
0.15y=15
y=15/0.15
y=100
Finally, you have to replace the value of y in (3) to find x:
x=162-100
x=62
Now, you know that James has 100 quarters and you can multiply this number for the value of a quarter to find the amount James has in quarters:
100*0.25=25
According to this, the answer is that James has $25 in quarters.
Answer:
1st: 3*root6 + 5
2nd: 35*root2 + 115
3rd: 24*root2 - 20*root6 + 15*root3 - 18
4th: 17*root6 - 38
5th: 13*root10 - 42
Step-by-step explanation:
To simplify these expressions we need to use the distributive property:
(a + b) * (c + d) = ac + ad + bc + bd
So simplifying each expression, we have:
1st.
(2 root 2 + root 3 ) ( 2 root 3 - root 2)
= 4*root6 - 2*2 + 2*3 - root6
= 3*root6 - 4 + 9
= 3*root6 + 5
2nd.
(root 5 + 2 root 10) (3 root 5 + root 10)
= 3 * 5 + root50 + 6*root50 + 2*10
= 15 + 5*root2 + 30*root2 + 100
= 35*root2 + 115
3rd.
(4 root 6 - 3 root 3) (2 root 3 - 5)
= 8*root18 - 20*root6 - 6*3 + 15root3
= 24*root2 - 20*root6 + 15*root3 - 18
4rd.
(6 root 3 - 5 root 2 ) (2 root 2 - root 3)
= 12*root6 - 6*3 - 10*2 + 5*root6
= 17*root6 - 18 - 20
= 17*root6 - 38
5th.
(root 10 - 3 ) ( 4 - 3 root 10)
= 4*root10 - 3*10 - 12 + 9*root10
= 13*root10 - 30 - 12
= 13*root10 - 42
