Answer:
The type of chemical mutagen to choose depends on the intended effect. In this case, the best ones are acridines and nitrous acid.
Explanation:
Brenner et al. proposed that acridines induce mutations by causing deletions or additions of single base pairs during replication. Acridines bind to DNA by intercalation between adjacent base pairs. Acridines inactivate extracellular phage by photodynamic action but the necessary conditions for this killing
are avoided in the procedure for acridine-induced mutation of reproducing phage. The lack of reported acridine-induced mutation in organisms other than phage raises some questions as to the generality of its
mutagenesis, thus making it a good type of compounds to induce specific mutations.
In the other hand, nitrous acid deaminates the amino bases adenine, cytosine (and hydroxymethylcytosine) , and guanine in nucleic acids.
Analysis of the effect of differences of pH during nitrous acid treatment
of phage DNA showed that the rate of killing was affected similarly to
the rate of guanine deamination, and that the rates of induced r mutation was affected similarly to the rates of adenine and hydroxymethylcytosine deamination. Ascribing the induced mutations to deamination of adenine and cytosine is reasonable in terms of the hydrogen bonding of their products and the Watson-Crick base pairing schemes. Since this inorganic acid is molecule-specific, it would also be used to induce certain mutations in bacteria without causing transition mutations.
Answer: The maximum amount of C that can be produced is 2.0 mol.
Explanation:
The balanced equation will be as follows.
![4A + 3B \rightarrow 4C](https://tex.z-dn.net/?f=4A%20%2B%203B%20%5Crightarrow%204C)
As we are given that,
moles of C = moles of A =
moles of B
When we react 2.0 mol A with 3.0 mol B then the limiting reagent is A as specie A has less number of moles. Therefore, the maximum amount of C which can be produced is as follows.
![\frac{2.0}{4} \times 4](https://tex.z-dn.net/?f=%5Cfrac%7B2.0%7D%7B4%7D%20%5Ctimes%204)
= 2.0 mol
Therefore, we can conclude that the maximum amount of C that can be produced is 2.0 mol.
<span><span>N2</span><span>O5</span></span>
Explanation!
When given %, assume you have 100 g of the substance. Find moles, divide by lowest count. In this case you'll end up with
<span><span>25.92 g N<span>14.01 g N/mol N</span></span>=1.850 mol N</span>
<span><span>74.07 g O<span>16.00 g O/mol O</span></span>=4.629 mol O</span>
The ratio between these is <span>2.502 mol O/mol N</span>, which corresponds closely with <span><span>N2</span><span>O5</span></span>.
Answer:
![\small \sf \: 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O \\ \small \sf \: 2 KNO_3 \rightarrow 2 KNO_2 + O_2 \\ \small \sf \: Ca + 2 H_2O \rightarrow \: Ca(OH)_2 + H_2 \\ \small \sf \: 2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2 \\ \small \sf \: 2 CO + O_2 \rightarrow \: 2 CO_2](https://tex.z-dn.net/?f=%20%20%5Csmall%20%5Csf%20%5C%3A%204NH_3%20%2B%205O_2%20%20%5Crightarrow%204NO%20%2B%206H_2O%20%5C%5C%20%20%20%5Csmall%20%5Csf%20%5C%3A%202%20KNO_3%20%20%5Crightarrow%202%20KNO_2%20%2B%20O_2%20%5C%5C%20%20%20%5Csmall%20%5Csf%20%5C%3A%20Ca%20%2B%202%20H_2O%20%20%5Crightarrow%20%5C%3A%20Ca%28OH%29_2%20%2B%20H_2%20%5C%5C%20%20%20%5Csmall%20%5Csf%20%5C%3A%202NaHCO_3%20%20%5Crightarrow%20Na_2CO_3%20%2B%20H_2O%20%2B%20CO_2%20%5C%5C%20%20%20%5Csmall%20%5Csf%20%5C%3A%202%20CO%20%2B%20O_2%20%20%5Crightarrow%20%5C%3A%202%20CO_2)
Explanation:
A) When four moles of ammonia reacts with five moles of O2 gas, four moles of Nitrogen mono oxide liberates along with six moles of water.
![\sf \: 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%204NH_3%20%2B%205O_2%20%20%5Crightarrow%204NO%20%2B%206H_2O)
B) When two moles pottasium nitrate (KNO3) is heated it dissociates into two moles of potassium nitrite liberates along with one mole of O2 gas.
![\sf \: 2 KNO_3 \rightarrow 2 KNO_2 + O_2](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%202%20KNO_3%20%20%5Crightarrow%202%20KNO_2%20%2B%20O_2)
C) When one mole of calcium reacts with two moles water, one mole of calcium hydroxide obtained & one of hydrogen gas released.
![\sf \: Ca + 2 H_2O \rightarrow \: Ca(OH)_2 + H_2](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20Ca%20%2B%202%20H_2O%20%20%5Crightarrow%20%5C%3A%20Ca%28OH%29_2%20%2B%20H_2)
D) When two mole of Sodium bicarbonate (NaHCO3) is heated it gradually decomposes to one mole of Sodium carbonate (Na2CO3) obtained along with one mole of each Water & Carbon dioxide.
![\sf \: 2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%202NaHCO_3%20%20%5Crightarrow%20Na_2CO_3%20%2B%20H_2O%20%2B%20CO_2)
E) <em>The question needs to corrected,</em>
When two moles of carbon monoxide reacts with one mole oxygen two moles of carbon dioxide is released.
![\sf \: 2 CO + O_2 \rightarrow \: 2 CO_2](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%202%20CO%20%2B%20O_2%20%20%5Crightarrow%20%5C%3A%202%20CO_2)
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