Question

For an experiment, you need to dissolve 0.14 mole of NaCl in 1 liter of water. How much NaCl must you weighout?

Answer 1

Answer:

option D is correct that is  8.2 g

Explanation:

Data Given:

mole of NaCl = 0.14 mol

Volume of water = 1 L

Weight of Nacl = ?

Solution:

In this we know the amount of NaCl and to find weight of NaCl to form a solution.

So,

Formula Used

    no. of moles = weight in g / Molar mass . . . . . . . . . . (1)

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5 g/mol

     

Rearrange equation (1)

        no. of moles = weight in g / Molar mass . . . . . . . . . . (1)

        weight of Nacl =  no. of moles x Molar mass . . . . . . . . . . (2)

Put values in the Equation 2

             weight of Nacl = 0.14 mol x 58.5 g/mol

              weight of Nacl = 8.2 g

weight of Nacl = 8.2 g

So option D is correct that is  8.2 g