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Anarel [89]
4 years ago
5

100 billion in scientific notation?

Chemistry
2 answers:
olga55 [171]4 years ago
6 0
100 billion (100,000,000,000) in scientific notation is 1*10^11
bulgar [2K]4 years ago
3 0

Answer: 1×10^11

Explanation:

<u>concept to know:</u> scientific notation must be written in the form of a × 10^b

where 0<a<10.

100 billion= 100,000,000,000

there are 11 zeros after 1

1 × 10^11

Hope this helps!! :)

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Read 2 more answers
Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

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Refer to the example about diatomic gases A and B in the text to do problems 19 - 27.
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Answer:a

Explanation:

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