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stiv31 [10]
3 years ago
11

The element with the greatest density is osmium, which has

Chemistry
1 answer:
Vinil7 [7]3 years ago
5 0

Answer:

Mass is 725.46g/cm

Explanation:

Mass = density × volume = 22.6g/cm^3 × 32.1cm^2 = 725.46g/cm

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Please help!!! Is it balanced or unbalanced?
Black_prince [1.1K]

Hey there!

I believe the answer you are looking for is Unbalanced!

If I am incorrect I am very sorry and would love any feedback.

Have a nice day, and Happy Halloween!

6 0
4 years ago
What is temperature? How do we measure temperature? What temperature unit were you supposed to record in the layers of the earth
OLga [1]

=The measure of warm and coldness of an object or substances with references to some standard value is known as temperature.

= We measure temperature by Fahrenheit (°F) scale, the Kelvin (K), and the Celsius (°C).

8 0
3 years ago
What is the lewis dot structure for N2Br4?​
Vera_Pavlovna [14]

Answer:

   ..                                ..

<h2>..Br-     ..    ..  -BR.. </h2><h2>   ..       N - N    ..</h2><h2>   ..                    ..</h2><h2>..Br-               - Br..    </h2>

   ..                                 ..

Explanation:

7 0
4 years ago
At a certain temperature this reaction follows first-order Kinetics with a rate constant of 0.0660
Juli2301 [7.4K]

Answer:

After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.

Explanation:

Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:

ln[HI] = -kt + ln [HI]₀

<em>Where [HI] is actual concentration after time t, </em>

<em>k is rate constant </em>

<em>and [HI]₀ is initial concentration of the reactant. </em>

Initial concentration of HI is 0.310M,

K is 0.0660s⁻¹,

And the actual concentration is 0.0558M:

ln[HI] = -kt + ln [HI]₀

ln[0.0558M] = -0.0660s⁻¹*t + ln [ 0.310M]

-1.7148 = -0.0660s⁻¹*t

26.0s = t

<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>

<em />

3 0
3 years ago
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb of energy
umka21 [38]

Answer:

See explanation below

Explanation:

First, you are not providing any data to solve this, so I'm gonna use some that I used a few days ago in the same question. Then, you can go and replace the data you have with the procedure here

The concentration of liquid sodium will be 8.5 MJ of energy, and I will assume that the temperature will not be increased more than 15 °C.

The expression to calculate the amount of energy is:

Q = m * cp * dT

Where: m: moles needed

cp: specific heat of the substance. The cp of liquid sodium reported is 30.8 J/ K mole

Replacing all the data in the above formula, and solving for m we have:

m = Q / cp * dT

dT is the increase of temperature. so 15 ° C is the same change for 15 K.

We also need to know that 1 MJ is 1x10^6 J,

so replacing all data:

m = 8.5 * 1x10^6 J / 30.8 J/K mole * 15 m = 18,398.27 moles

The molar mass of sodium is 22.95 g/mol so the mass is:

mass = 18,398.27 * 22.95 = 422,240.26 g or simply 422 kg rounded.

5 0
4 years ago
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