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Leokris [45]
3 years ago
15

How does gamma radiation differ from alpha or beta particle radiation?

Physics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

1.

Explanation:gamma rays are the most powerful in the electromagnetic spectrum and they are a result of a radioactive atom.they aren't made of matter but just energy as a wave.

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An object with the mass of 2.0 kg accelerates 2.0 m/s2 when an inknown force is applied to it what is the amount of the force
Ivahew [28]

As per Newton's II law we know that

F = ma

here F = force applied

m = mass of object = 2 kg

a = acceleration = 2 m/s^2

now as per above formula we will have

F = 2 \times 2

F = 4 N

so here applied force on the ball will be 4 N

3 0
3 years ago
Describe an example of newton’s 3rd law of motion
professor190 [17]

Answer:

For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

8 0
3 years ago
A cat walks across the kitchen with a constant speed of 0.5 m/s. How long does it take the cat to walk 8 m?
ruslelena [56]
How does the cat walk-
4 0
3 years ago
You hear a sound with a frequency of 256 Hz. The amplitude of the sound increases and decreases periodically: It takes 2 seconds
Fiesta28 [93]

These 255.75 Hz and 256.25 Hz sounds can be thought of as a sum of two waves with frequencies.

Answer: Option A

<u>Explanation:</u>

To solve this, it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.

Let frequency of beat = f

The relationship that defines both agreements is given by the equation,

                f=\frac{1}{T}

Then the frequency for the previous period given (2sec) is

               f=\frac{1}{2}=0.5

The beat frequency of two frequencies is equal to the difference between the two frequencies, then

               f=\left|f_{1}-f_{2}\right|

               f=|255.75-256.25|=0.5 H z

Hence, Option A is correct.

Similarly we can check like these for other options too as below,

For option B, f=|255.5-256.5|=1 Hz.

For Option C, f=|255-257|=2 H z

For Option D, f=|254-258|=4 H z

For Option E, f=|256-2|=254 H z

Therefore, the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz.

8 0
3 years ago
The security alarm on a parked car goes off and produces a frequency of 813 Hz. The speed of sound is 343 m/s. As you drive towa
True [87]

Answer:

You are driving at Vo= 15.2 m/s = 54.72 km/h

Explanation:

Δf= 72.1 Hz

f= 813 Hz

v= 343 m/s

Δf= f* [ (v-(-vo) / v) - ( v-(vo) / v) ]

clearing vo:

Vo= 15.2 m/s

5 0
4 years ago
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