Going to college and passing all your classes
Answer:
1609.1429 rad/sec
Explanation:
By using the relation Angular velocity and frequency as:
Angular velocity (ω) = 2×π×Frequency (ν)
Given the frequency = 256 vibrations per second.
So, Angular velocity can be calculated by using the above formula as:
Angular velocity (ω) = 2×π×Frequency (ν)
⇒Angular velocity (ω) = 2×π×256 rad/ sec
⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec
<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>
The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.
When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.
Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.
So the light of "bulb a" will be dimmer.
The correct answer to this question is false
Answer:
See explanation
Explanation:
We have to convert to angular velocity in rads-1 as follows;
Angular velocity in rad/s = 2π/60 × 1900 rpm = 199 rad/s
Given that
angular velocity =angle turned /time taken
Time taken = angle turned/angular velocity
Converting 35° to radians we have;
35 × π/180 = 0.61 radians
Time taken = 0.61 radians/199 rad/s
Time taken = 0.0031 seconds
