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Alona [7]
3 years ago
13

Consider two copper wires of the same length. One has twice the cross-sectional area of the other. How do the resistances of the

se two wires compare? Consider two copper wires of the same length. One has twice the cross-sectional area of the other. How do the resistances of these two wires compare? Both wires have the same resistance. The thicker wire has twice the resistance of the shorter wire. The thicker wire has half the resistance of the shorter wire. none of the given answers
Physics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer: a) when the cross section is doubled the resultant resistence  is a half. This means the thicker wire have half resistence than the thinner wire.

Explanation: In order to explain this behaviur we have to consider the expresion for the resistence which is given by:

R=\frac{\epsilon o  L}{A} where L and A are the length and the cross section for the wire, respectively.

From this expresssion we can conclude the above, this means

R=εo*L/A  if A is now 2A we have

R' = εo*L/2*A= R/2

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When solid surfaces slide over each other, the kind of friction that occurs is called_____ friction.
expeople1 [14]

Answer:

Sliding Friction

Explanation:

The term sliding friction refers to the resistance created by two objects sliding against each other. This can also be called kinetic friction. Sliding friction is intended to stop an object from moving.

7 0
3 years ago
Read 2 more answers
A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a
Anton [14]

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

5 0
3 years ago
What is the volume of an object if it has a mass of 10 grams and a density of 87 g/ml
belka [17]

Answer:

<h3>The answer is 0.115 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 10 g

density = 87 g/ml

We have

volume =  \frac{10}{87}  \\  = 0.114942528...

We have the final answer as

<h3>0.115 mL</h3>

Hope this helps you

5 0
3 years ago
Line d represents water. if the atmospheric pressure in a flask is lowered to 70 kpa, water would boil at what temperature?
sp2606 [1]
The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C

In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.

Doing so, you can see that you are at a value a little bit above 90 °C (see picture).

Hence, the correct answer is C) 92°C.

5 0
3 years ago
Now instead a 3-mw laser of wavelength λ = 760 nm is directed into the interferometer (with the mirror m1 at the displacement ca
slavikrds [6]

power received will always remain same and does not depends on the distance

it will be same as the power of source

P = 3 mW

now the energy released by one photon is given as

E = \frac{hc}{\lambda}

E = \frac{6.6* 10^{-34}* 3 * 10^8}{760 * 10^{-9}}

E = 2.6 * 10^{-19} J

now let say N photons per second released

N * 2.6 * 10^{-19} = 3 * 10^{-3}

N = 1.15* 10^{16} per\: second

7 0
3 years ago
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