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2 years ago

2. Your latitude indicates how far you are from the equator, a

Physics

1 answer:

marshall27 [118]2 years ago

5 0

The characteristics of the shadow allow to find the result for the change of the sun's rays are:

As the person advances from the equator to the poles the rays are less perpendicular, which is reflected in a longer shadow.

The shade is a space where the sun's rays do not reach.

When the person is at the equator, his shadow is very small, indicating that the rays are falling vertically.

As the person increases his latitude, a shadow begins to appear every larger shade, due to two processes:

The earth is spherical, therefore there is an angle between the normal to the earth's surface and the sun's ray , which is why there is a region where the sun does not reach.

The Earth has an inclination with respect to the sun and this inclination changes in the course of the year.

When the person is just over the north pole, the shadow should be infinite, which indicates that the person is parallel to the sun's rays. In reality, due to the inclination of the earth, the shadow is very long, but finite.

In conclusion using the characteristics of the shadow we can find the result for the change of the sun's rays are:

As the person advances the sun's rays are less perpendicular, which is reflected in a longer shadow.

Learn more sun's ray and latitude here: brainly.com/question/3005929

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A soccer player is running upfeild at 10m/s and comes to a stop in 3 seconds facing in the same direction what is his accelerati

kumpel [21]

-3.33 m/s^2

The soccer player decelerates from 10 m/s to 0 m/s. Because he decelerates the acceleration will be a negative value. Since he takes 3 seconds to decelerate, divide his original velocity by 3

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3 years ago

A neutral atom of an element has the same number of __________ and ________. Question 6 options: Neutrons and electrons Protons

Bess [88]

The answer is: [C]: "protons and electrons" .
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3 years ago

A car is traveling at 96km/hr. what is the acceleration of a car traveling a distance of 100m and come to rest?

8090 [49]

Answer:

Explanation:

v² = u² + 2as

v = 0

u = 96 / 3.6 = 26.7 m/s

0² = 26.7² + 2a100

a = -3.5555555... ≈ -3.6 m/s²

the negative sign indicated the acceleration vector opposes the (assumed positive) initial velocity vector direction.

6 0

2 years ago

What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa

dlinn [17]

Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}$

$E=3.315\times10^{-17}\ J$

(b). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}$

$E=6.709\times10^{-21}\ J$

(c). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}$

$E=3.315\times10^{-11}\ J$

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}$

$E=6.709\times10^{-9}\ J$

Hence, This is the required solution.

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3 years ago

Explain a situation in which you can accelerate even though your speed doesn’t change.

Serga [27]

"Acceleration" does NOT mean speeding up. It also doesn't mean
slowing down. Acceleration means ANY change in the speed
OR DIRECTION of motion.

The only kind of motion that's NOT accelerated is motion at a steady
speed AND in a straight line.

Even when your speed is steady, you're accelerating if your direction
is changing.

A few examples:
(no speeds are changing):

-- driving on a curved road, or turning a corner
-- going around a curve on a skateboard, a bike, or a Segway
-- running on a quarter-mile track
-- an Indy car cruising a practice lap around the track
-- water spinning, getting ready to go down the drain
-- any point on the blade of a fan
-- the little ball going around the inside of a Roulette wheel
-- the Moon in its orbit around the Earth
-- the Earth in its orbit around the sun

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3 years ago