Some scientist believe that the ozone layers of the earth had been weakening and the waters or current changes direct ever 5-7 month.
<h3>
Answer:</h3>
209.236 kg · m/s
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Momentum</u>
Momentum Formula: P = mv
- P is momentum (in kg · m/s)
- m is mass (in kg)
- v is velocity (in m/s)
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
m₁ = 87.2 kg
v₁ = 2.87 m/s
m₂ = 0.0520 kg
v₂ = 789 m/s
<u>Step 2: Find Momentums</u>
<em>Football Player</em>
- Substitute [MF]: P = (87.2 kg)(2.87 m/s)
- Multiply: P = 250.264 kg · m/s
<em>Bullet</em>
- Substitute [MF]: P = (0.0520 kg)(789 m/s)
- Multiply: P = 41.028 kg · m/s
<u>Step 3: Find difference</u>
- Define equation: P₁ - P₂
- Substitute: 250.264 kg · m/s - 41.028 kg · m/s
- Subtract: 209.236 kg · m/s
<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.
Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.
Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.
Simply put it, take note of the following conversions:
- 1 gram of carbohydrate is 4kcal
- 1 gram of protein is also 4kcal
- Though, 1 gram of fat is 9kcal
So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.
1. 25g x 4kcal/g = 100kcal
2. 6g x 4kcal/g = 24kcal
3. 5g x 9kcal/g = 45kcal
4. 100kcal + 24kcal + 45kcal = 169kcal!
Therefore, the food contains 169 kilo-calories!
You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283
#SPJ4
Answer: 17.68 s
Explanation:
This problem is a good example of Vertical motion, where the main equation for this situation is:
(1)
Where:
is the height of the ball when it hits the ground
is the initial height of the ball
is the initial velocity of the ball
is the time when the ball strikes the ground
is the acceleration due to gravity
Having this clear, let's find
from (1):
(2)
Rewritting (2):
(3)
This is a quadratic equation (also called equation of the second degree) of the form
, which can be solved with the following formula:
(4)
Where:



Substituting the known values:
(5)
Solving (5) we find the positive result is:

Hi there!

Use the equation:

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391

