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Natalka [10]
3 years ago
14

State examples of a transverse wave. ​

Physics
2 answers:
blondinia [14]3 years ago
7 0

Answer

Light and other types of electromagnetic radiation are examples of transverse waves. Some other examples of transverse waves include a ripple on a pond and a wave in a string.

laiz [17]3 years ago
6 0

ripples on the surface of water.

vibrations in a guitar string.

a Mexican wave in a sports stadium.

electromagnetic waves – eg light waves, microwaves, radio waves.

seismic S-waves.

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What is the definition of Mutualism
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Mutualism is a long-term relationship where two organisms interact in such a way that both of them benefits from that relationship.

For example, there is a relationship between a bird called "oxpecker", and a rhino. While the bird eats the harmful bugs (eg. tick) on the rhino's skin and relieves its hunger; the rhino gets rid of the bugs that harm it.
5 0
3 years ago
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There are only 2 GENDERS and it proven with science
VikaD [51]

Answer:

https://young.scot/get-informed/national/gender-identity-terms

Explanation:

6 0
3 years ago
As a train accelerates uniformly, it passes successive 5-kilometer markers while traveling at velocities 10 m/s and 25 m/s. what
gregori [183]
<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
8 0
3 years ago
You are in downtown Chicago (where streets run N-S and E-W). You started from 600 N. Michigan Avenue, and walked 3 blocks toward
pickupchik [31]

Answer:

Displacement is 565.69 m at 45° west of north

Explanation:

Let north represent positive y axis and east represent positive x axis.

We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.

3 blocks toward north = 300 j m

4 blocks toward west = -400 i m

1 blocks toward north = 100 j m

Total displacement = -400 i + 400 j m

Magnitude

     s=\sqrt{(-400)^2+400^2}=565.69m

Direction,

     \theta =tan^{-1}\left ( \frac{400}{-400}\right )=135^0

     Direction is 45° west of north.

Displacement is 565.69 m at 45° west of north

4 0
3 years ago
Two charges are separted by a distance d and exert mutual attractive forces of f on each other. If the charges are separated by
ASHA 777 [7]

The new force between the charges when the distance become 2d will be  F'=4F

<h3>What is electrostatic force?</h3>

When two charged particles are separated by the distance d then the force of attraction or repultion acts on the charged particle depending upon the nature of the charge whether it is positive or negative.

The formula for the electrostatic force is given by

F=\dfrac{kq_1q_2}{d^2}

Now if the value of d becomes 2d then the formula will become:

F'=\dfrac{kq_1q_2}{(2d)^2}=\dfrac{kq_1q_2}{4d}

\dfrac{F'}{F}=\dfrac{1}{4}

F=4F'

Hence the new force between the charges when the distance become 2d will be  F'=4F

To know more about electrostatic force follow

brainly.com/question/17692887

#SPJ4

3 0
2 years ago
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