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Natalija [7]
3 years ago
14

In the diagram, which angles from a linear pair ? Select 3 options

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
RST and RSV
RST and VSU
TSU and USV
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What is the greatest common factor of 12 and 18? *<br><br> 1. 6<br> 2. 3<br> 3. 2<br> 4. 9
Dafna11 [192]
The greatest common factor of 12 and 18 is 6.
3 0
2 years ago
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How to tell if its identifying functions is <br> a function or not
Svetach [21]

Answer:

Step-by-step explanation:

Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function.

6 0
2 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
List 3 values that make 24&lt;y +u true
Andrei [34K]
Y=2 u=6

y=8 u=12

y=10 u=11
4 0
3 years ago
Solve for k. k/2 +1/2=3
ikadub [295]

Answer:

k = 5

Step-by-step explanation:

Solve for k :

\frac{k}{2} + \frac{1}{2} = 3

-Multiply both sides of the equation by the denominator 2 :

2 \times \frac{k}{2} + \frac{1}{2} = 3 \times 2

k + 1 = 6

-Subtract both sides by 1:

k + 1 - 1 = 6 - 1

k = 5

So, the value of k is 5.

7 0
2 years ago
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