All categories

3 years ago

Friction is generated when _____ interact with each other on sliding surfaces.

Physics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

Friction is generated when <u>molecules</u> interact with each other on sliding surfaces.

Explanation:

As we know that friction force is the contact force between two surfaces. When two surface are placed over each other then in that case molecules of one surface are in contact with the molecules of other surface.

Due to the close interaction all the molecules will form a weak attraction force which will make them bonded with each other.

Now due to this weak bond when we move one surface relative to other surface then we need the force to break the bond between two surface which is known as friction force.

So here we can say that

Friction is generated when <u>molecules</u> interact with each other on sliding surfaces.

vladimir1956 [14]3 years ago

7 0

Friction is generated when 2 solid surfaces interact

You might be interested in

A 20 m high filled water tank develops a 0.50 cm hole in the vertical wall near the base. With what speed does the water shoot o

Rina8888 [55]

Answer:

The speed of the water shoot out of the hole is 20 m/s.

(d) is correct option.

Explanation:

Given that,

Height = 20 m

We need to calculate the velocity

Using formula Bernoulli equation

$\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}$

Where,

v₁= initial velocity

v₂=final velocity

h₁=total height

h₂=height of the hole from the base

Put the value into the formula

$v_{1}^2=2g(h_{2}-h_{1})$

$v_{1}=\sqrt{2g(h_{2}-h_{1})}$

$v_{1}=\sqrt{2\times9.8\times(20-0.005)}$

$v_{1}=19.7\ m/s= approximate\ 20\ m/s$

Hence, The speed of the water shoot out of the hole is 20 m/s.

7 0

3 years ago

After a displacement of 17 m, a train on a straight track is at the position xf = –2.5 m

EastWind [94]

-19.5m

-19.5+17=-2.5m

5 0

3 years ago

Read 2 more answers

You throw a balloon that floats in the air with a velocity of 2 m / s south . If the wind speed is 5 m / s west , how far south

zvonat [6]

Answer:

The distance traveled by the balloon is 10.77 m

Explanation:

velocity of the ball, $v_b$ = 2 m/s south

velocity of the air, $v_a$ = 5 m/s west

To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.

| 2m/s

↓

5m/s ←------------------

the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.

R² = 5² + 2²

R² = 29

R = √29

R = 5.385 m/s

The distance traveled by the balloon is calculated as;

d = R x t

where;

t is time of the motion = 2 seconds

d = 5.385 x 2

d = 10.77 m

Therefore, the distance traveled by the balloon is 10.77 m.

4 0

3 years ago

The mass of a ship before launch is 55,000 metric tons. The ship is launched down a ramp and drops a total of 10 vertical meters

skelet666 [1.2K]

Answer:

ΔT = 17.11 °C

Explanation:

In this case, we have a ship standing on a place with a given mass and it's about to be launched to a lock containing water.

At first, before launch, the ship has a potential energy, and when the ship hits the water after being launched, this potential energy is transformed into kinetic energy.

So, let's calculate first the potential energy of the ship:

E = mgh (1)

We have the mass, gravity and height, so we need to replace the given data here. Before we do that, let's remember to use the correct units. A ton is 1000 kg, so replacing and converting we have:

E = (55000 ton * 1000 kg/ton) * (9.8 m/s²) * 10 m

E = 5.39x10⁹ J

Now this energy will be the same when the ship hits the water, only that is kinetic energy that will result in the rise of temperature. To get this rise we use the following expression:

E = m * C * ΔT (2)

We have the energy, the mass of water (assuming density of water as 1 kg/m³) and the specific heat, so, replacing in (2) and solving for ΔT we have:

ΔT = E / m * C (3)

ΔT = 5.39x10⁹ / 4200 * 75000

Hope this helps

5 0

3 years ago

By what factor is the self-inductance of an air solenoid changed if its length and number of coil turns are both tripled

fredd [130]

Answer:

The new self inductance is 3 times of the initial self inductance.

Explanation:

The self inductance of a solenoid is given by :

$L=\dfrac{\mu_oN^2 A}{L}$

Where

N is number of turns per unit length

A is area of cross section

l is length of solenoid

If length and number of coil turns are both tripled,

l' = 3l and N' = 3N

New self inductance is given by :

$L'=\dfrac{\mu_oN'^2 A}{L'}\\\\=\dfrac{\mu_o(3N)^2 A}{3L}\\\\=3\dfrac{\mu_oN^2 A}{L}\\\\=3L$

So, the new self inductance is 3 times of the initial self inductance.

4 0

3 years ago