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The wavelength of the interfering waves is 3.14 m.
<h3>Calculation:</h3>
The general equation of a standing wave is given by:
y = 2A sin (kx) cos (ωt) ......(1)
The given equation represents the standing wave produced by the interference of two harmonic waves:
y = 3 sin (2x) cos 5t .......(2)
Comparing equations (1) and (2):
k = 2
We know that,
k = 2π/λ
λ = 2π/k
λ = 2 (3.14)/ 2
λ = 3.14 m
Therefore, the wavelength of the interfering waves is 3.14 m.
I understand the question you are looking for is this:
Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t where x is in m and t is in s. What is the wavelength of the interfering waves?
Learn more about interfering waves here:
brainly.com/question/2910205
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Answer:
925.04 J/s
Explanation:
T = 80 C = 80 + 273 = 353 K
To = 20 c = 20 + 273 = 293 K
A = 2 m^2
Use the formula for Stefan's law
Energy radiated per second


E = 925.04 J/s
Answer:
Approximately
and approximately
.
Explanation:
Let
and
denote the capacitance of these two capacitors.
When these two capacitors are connected in parallel, the combined capacitance will be the sum of
and
. (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)
.
On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:
.
(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field (
) between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored
stays the same.)
The question states that:
, and
.
Let the capacitance of these two capacitors be
and
. The two equations will become:
.
From the first equation:
.
Hence, the
in the second equation here can be replaced with
. That equation would then become:
.
Solve for
:
.
.
.
Solve this quadratic equation for
:
or
.
Substitute back into the equation
for
:
In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately
and approximately
(both values are rounded to two significant digits.)
Power = work / time --> time = work / power = 3600 J / 275 watts = 13.1 seconds.
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