Here as we can see that weight on the right side of ruler given as D is applying torque about the fulcrum this is counter balanced by weight on left side given as A

now by torque balance we can say

$W_aL_a = W_bL_b$

now we will have

$W_a = W_b\times \frac{L_b}{L_a}$

now here as per given setup we can see that

$L_b > L_a$

so here we will have

$W_a > W_b$

so the weight required to hold D will be more and correct answer will be

<em>The setup increases the amount of force required to lift the block and, therefore, decreases your mechanical advantage.</em>

8 0

4 years ago

PLEASE HELP I can't figure it out

PSYCHO15rus [73]

D. I know that like the back of my hand

4 0

4 years ago

Consider water flowing through a cylindrical pipe with a variable cross-section. The velocity is v at a point where the pipe dia

Harrizon [31]

Answer:

one ninth

Explanation:

d = 1 cm , v = v

D = 3d, V = ?

By the equation of continuity,

A V = a v

3.14 x D^2 / 4 x V = 3.14 x d^2 / 4 x v

9d^2 x V = d^2 x v

V = v / 9

Thus, the velocity becomes one ninth the initial velocity

5 0

3 years ago