Answer:
Force constant, k = 653.3 N/m
Explanation:
It is given that,
Weight of the bag of oranges on a scale, W = 22.3 N
Let m is the mass of the bag of oranges,


m = 2.27 kg
Frequency of the oscillation of the scale, f = 2.7 Hz
We need to find the force constant (spring constant) of the spring of the scale. We know that the formula of the frequency of oscillation of the spring is given by :



k = 653.3 N/m
So, the force constant of the spring of the scale is 653.3 N/m. Hence, this is the required solution.
Answer:
Acceleration, 
Explanation:
Given that,
Speed of pilot, v = 475 m/s
Radius of the circle, r = 2310 m
If the pilot is moving in a circular path, it will experience a centripetal acceleration. It is given by the formula as :



So, the acceleration experienced by a pilot flying in a circle is
. Hence, this is the required solution.
The magnitude of the resulting acceleration of the block is 6.14 m/s².
The given parameters;
- <em>mass of the block, m = 2.2 kg</em>
- <em>horizontal force on the block, F = 27 N</em>
- <em>force below the horizontal, 81 N at 60⁰</em>
The net horizontal force on the block is calculated as follows;

The acceleration of the block is calculated as follows;

Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².
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