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kobusy [5.1K]
4 years ago
8

An object with a mass of 20kg is pushed with a force of 60 Newtons(N). What is the object’s acceleration?'

Physics
2 answers:
balandron [24]4 years ago
4 0

Answer:

\Huge \boxed{\mathrm{3 \ m/s^2}}

Explanation:

\sf \displaystyle acceleration \ (m/s^2) = \frac{force \ (N)}{mass \ (kg)}

\displaystyle a = \frac{F}{m}

The mass of the object is 20kg

The force of 60 N is acting on the object.

\displaystyle a = \frac{60}{20}

a=3

The acceleration of the object is 3 m/s².

jenyasd209 [6]4 years ago
3 0

Answer: a=3m/s^2

Explanation:

Formula: F=m*a

Where;

F = force

m = mass

a = acceleration

Solve for a;

a=\frac{F}{m}

a=\frac{60N}{20kg}

a=3m/s^2

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According to the article, men experience more bone loss as they get older? options: True False
KonstantinChe [14]

Answer:

true

Explanation:

7 0
3 years ago
Read 2 more answers
An inductor with L = 9.80 mH is connected across an ac source that has voltage amplitude 41.5 V . What value for the frequency o
sashaice [31]

Answer:

149.8Hz

Explanation:

V=I.(XL).........{1}

where (XL) is inductive reactance

(XL) =2πfL......... {2}

V= 41.5, l= 4.5, L= 9.8* 10^-³

take π to be 3.14

(XL) = V/I

= 41.5/4.5

= 9.22

f = (XL) /2πL

= 9.22* 10^³/6.28* 9.8

=149.8

7 0
3 years ago
a motorcycle traveling on the highway at a velocity of 120 kilometre-per-hour passes a car traveling at a velocity of 90 kilomet
musickatia [10]

Answer:

The relative velocity of the motorcycle to a passenger in the car is 30 km/h

Explanation:

The question relates to the principle of relative velocity and reference frames

The given parameters are;

The velocity of the motorcycle, v₁ = 120 km/h

The velocity of the car, v₂ = 90 km/h

The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as \underset{v}{\rightarrow}_{X|Y} = \underset{v}{\rightarrow}_{X} - \underset{v}{\rightarrow}_{Y}

Therefore, the relative velocity of the motorcycle to the car is v_{1|2} = v₁ -  v₂, which give;

v_{1|2}  = 120 km/h - 90 km/h = 30 km/h

The relative velocity of the motorcycle to a passenger in the car = 30 km/h.

5 0
3 years ago
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
3 years ago
Suppose that the speed of yellow visible light in a certain transparent medium is 2.01* 105 km/s. What, approximately, is the in
True [87]

Answer:

1.50

Explanation:

Index of refraction:

n=\frac{c}{v} where n is the refractive index, c is the speed of light in vacuum and v is the speed of light in medium.

The speed of light in vacuum is 3.00 \times 10^5 \text{km/s}

Speed of light in medium is 2.01 \times 10^5 \text{km/s}

Thus,

n=\frac{3.00\times 10^5}{2.01\times 10^5}

n=1.50

Index of refraction of this substance through yellow light is 1.50

4 0
3 years ago
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