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kobusy [5.1K]
4 years ago
8

An object with a mass of 20kg is pushed with a force of 60 Newtons(N). What is the object’s acceleration?'

Physics
2 answers:
balandron [24]4 years ago
4 0

Answer:

\Huge \boxed{\mathrm{3 \ m/s^2}}

Explanation:

\sf \displaystyle acceleration \ (m/s^2) = \frac{force \ (N)}{mass \ (kg)}

\displaystyle a = \frac{F}{m}

The mass of the object is 20kg

The force of 60 N is acting on the object.

\displaystyle a = \frac{60}{20}

a=3

The acceleration of the object is 3 m/s².

jenyasd209 [6]4 years ago
3 0

Answer: a=3m/s^2

Explanation:

Formula: F=m*a

Where;

F = force

m = mass

a = acceleration

Solve for a;

a=\frac{F}{m}

a=\frac{60N}{20kg}

a=3m/s^2

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A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball
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(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s

(b) The work that the racket does on the ball is -35.1 Joule

<h3>Further Explanation</h3>

<u>Given :</u>

mass of ball = m = 0.06 kg

initial velocity = v₁ = -50.4 m/s

final velocity = v₂ = 37.0 m/s

<u>Unknown :</u>

(a) Impulse = I = ?

(b) Work = W = ?

<u>Solution :</u>

<h2>Question (a) :</h2>

In this question , we could use the formula from Second Law of Newton :

I = \Delta p

I = p_2 - p_1

I = m \times v_2 - m \times v_1

I = m \times (v_2 - v_1)

I = 0.06 \times (37.0 - (-50.4))

I = 0.06 \times (87.4)

I = 5.244~kg.m/s

\large { \boxed {I \approx 5.24~kg.m/s} }

<h2>Question (b) :</h2>

W = F \times d

W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)

W = \frac{I(v_1 + v_2)}{2}

W = \frac{5.244(-50.4 + 37)}{2}

W = \frac{5.244(-13.4)}{2}

W = -35.1348~Joule

\large { \boxed {W \approx -35.1~Joule}}

<h3>Learn more</h3>

Newton's Law of Motion: brainly.com/question/10431582

Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

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Answer:

The answer is based on the conservation of energy law; something you should really understand by now.  

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So the moving charge, call it q, has total energy TE = PE. It's all potential energy as we start with q not moving.  

It has potential energy because in order to separate q from Q, we had to do work, add energy, on q. And from the COE law, that work added is converted into PE.  

It's a bit like lifting something off the ground. That's work and it becomes GPE. So there's some work, in separating the two charges in the first place.  

But there's more.  

Now we let q go. As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.  

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