Science, a system of knowledge.
Answer:
Where are the categories, we need an image for reference or something to better understand the question
Answer:
a) Watch the attaccment
b) Ethyl bromide is more reactive than n-propyl bromid, and this more than neopentyl bromide. Ethyl bromide has less steric hindrance than the others, to SN2 reactions.
c) t-butyl bromide is more reactive than isopropyl bromide, and this more than ethyl bromide. t-butyl bromide structure stabilize the carbocation, better than the others.
Explanation:
Speed of SN2 reactions depends on steric hindrance, the less hindrance, the most reaction speed, meaning more reactivity. Then, those linear structures are more reactive to SN2 reactions.
In the other hand, speed of SN1 reactions depends on the stability of the carbocation formed. Structure with ramifications can stabilize better the carbocation, these structures are more reactive to SN1 reactions.
The dissolution of a solute in a solvent to form a solution usually occur in three steps, which are delta H1, delta H2 and delta H3.
For dissolving an ionic solid, the lattice energy, which is the energy that is holding the ionic particles in place correspond to DELTA H2 and it is the energy that must be conquered. The higher the charge in the ionic solid, the higher the lattice energy. The lattice energy must be overcome in order for the solid to dissolve.