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BaLLatris [955]
3 years ago
13

Calculate the PH of 0.25mol H2SO4

Chemistry
1 answer:
Hoochie [10]3 years ago
7 0

<span>This problem uses the relationship between Ka and the concentrations of the ions. Calculations are as follows:</span>

<span>
</span><span>1.9 x 10-5</span>= x^2 / (0.25 - x)

<span>x is very small and the denominator is approximately equal to 0.25. Thus, x is 2.2 x 10^-3

</span><span>pH = -log (2.2 x 10^-3)</span> = 2.66

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