Water solubility of oxygen at 25oC and pressure = 1 bar is at 40 mg/L water. In air with a normal composition the oxygen partial pressure is 0.2 atm. This results in dissolution of 40 . 0.2 = 8 mg O2/L in water that comes in contact with air.
Answer is: catabolism.
Missing question:
Synthesis.
Catabolism.
Rearrangement.
Anabolism.
Catabolism (<span>the set of </span>metabolic<span> pathways)</span> breaks down large molecules (in this example glycogen, a polysaccharide) into smaller units (in this example glucose, a monosaccharide).
Glycogen is <span>the main storage form of glucose in the body.</span>
No one can do that by him or her self
Answer:
0.54 J/goC
Explanation:
Recall that we define the heat transferred as ;
H= mcθ
Where;
H= heat transferred = 112300J
m= mass of the metal= 240g or 0.24 Kg
c= specific heat capacity of the metal = the unknown
θ= change in temperature = (880°C-13°C) = 867°C
Substituting values and making the specific heat capacity the subject of the formula;
c= H/mθ
c= 112300/ 240×867
c= 0.54 J/goC
Hence, the specific heat capacity of the metal is 0.54 J/goC.
