All categories

2 years ago

Evaluate −4x−y+4 when x=−14 and y=3. The value of the expression is _____ ?

Mathematics

1 answer:

Effectus [21]2 years ago

7 0

Answer:

The value of the expression is 57 :D

Step-by-step explanation:

Since x = -14 and y = 3, we need to replace the variables with the given numbers:

-4(x) - y + 4 =

-4(-14) - 3 + 4 =

56 - 3 + 4 =

53 + 4 = 57

You might be interested in

Y=-3x+4 solved for y

Sauron [17]

Y= -3x+4 should be 0

7 0

2 years ago

Read 2 more answers

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

2 years ago

Find the area of the parallelogram shown below.<br> 5<br> 4<br> square units

alina1380 [7]

Length times width and that will get you an answer

6 0

2 years ago

Which of the following is the quotient of rational expressions shown below?

emmasim [6.3K]

Answer: 6x - 3 over x^3

Step-by-step explanation:

7 0

2 years ago

Solve -vp+40<95 for v

Leya [2.2K]

-vp+40<95

subtract 40 from each side

-vp < 55

divide by -p (which flips the inequality) assuming p>0

v > -55/p

5 0

2 years ago