I think the velocity will be 300
Answer:
The atomic mass of an element is the average mass of the atoms of an element, according to google. Sum of protons and neutrons in nucleus is the mass number and multiply by 1 amu gives you the mass of the atom
Answer:
![V = IR](https://tex.z-dn.net/?f=V%20%3D%20IR)
Explanation:
Required
Which equation represents ohm's law?
Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).
Mathematically, this can be represented as:
![I\ \alpha\ \frac{V}{R}](https://tex.z-dn.net/?f=I%5C%20%5Calpha%5C%20%5Cfrac%7BV%7D%7BR%7D)
Convert the expression to an equation
![I\ =\ \frac{V}{R}](https://tex.z-dn.net/?f=I%5C%20%3D%5C%20%5Cfrac%7BV%7D%7BR%7D)
Multiply both sides by R to make V the subject
![I\ * R\ =\ \frac{V}{R} * R](https://tex.z-dn.net/?f=I%5C%20%2A%20R%5C%20%3D%5C%20%5Cfrac%7BV%7D%7BR%7D%20%2A%20R)
![I\ * R\ =V](https://tex.z-dn.net/?f=I%5C%20%2A%20R%5C%20%3DV)
Reorder
![V = I\ * R](https://tex.z-dn.net/?f=V%20%3D%20I%5C%20%2A%20R)
![V = IR](https://tex.z-dn.net/?f=V%20%3D%20IR)
<em>Option (a) is correct; Others are not</em>
Answer:
The work done by the force on the particle is 29.85 J.
Explanation:
The work is given by:
![W = ^{x_{2}}_{x_{1}}\int F_{x} dx](https://tex.z-dn.net/?f=%20W%20%3D%20%5E%7Bx_%7B2%7D%7D_%7Bx_%7B1%7D%7D%5Cint%20F_%7Bx%7D%20dx%20)
Where:
x₁: is the lower limit = 0 m
x₂: is the upper limit = 1.9 m
Fₓ: is the force in the horizontal direction = (4.5 + 13.7x - 1.5x²)N
![W = 29.85 J](https://tex.z-dn.net/?f=W%20%3D%2029.85%20J)
Therefore, the work done by the force on the particle is 29.85 J.
I hope it helps you!
Answer:
Explanation:
Total heat gain by the block ΔQ = 2 x 12 kJ = 24 kJ .
Gain of potential energy = mgh = 12 x 9.8 x 32 = 3.763 kJ
Decrease in kinetic energy KE = 1/2 x 12 ( 40² - 7² )
= 9.306 kJ
increase in internal energy ΔE = 70 kJ
ΔQ = ΔE + PE - KE + W , W is work done by the gas
Putting the values
24 = 70 + 3.763 - 9.306 + W
W = - 40.457 kJ .
Since W is negative that means work is done on the system .