What can be found in every skeletal muscle?
2 answers:
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This question is incomplete, the missing image uploaded along this answer below;
Answer:
a) frequency is 2.381 Hz
b) the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field is 0.5199 T
Explanation:
Given that;
cross sectional Area A = 0.018 m²
Number of turns N = 200
from the diagram. maximum time T = 0.42 sec
a) the frequency f of the generator in hertz
frequency = 1 / T
we substitute
frequency = 1 / 0.42 = 2.381 Hz
Therefore, frequency is 2.381 Hz
b) the angular frequency in rad/s
angular speed ω = 2πf
we substitute
ω = 2π × 2.381
ω = 14.96 rad/s
Therefore, the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field.
to determine the magnitude of the magnetic field, we use the following expression;
e = NBAω
from the diagram, e = 28.0 V
so we substitute
28.0 V = 200 × B × 0.018 × 14.96
28 = 53.856B
B = 28 / 53.856
B = 0.5199 T
Therefore, the magnitude of the magnetic field is 0.5199 T
Answer:
Work done, W = 1786.17J
Explanation:
The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "
Mass of a painter, m = 75 kg
He climbs 2.75-m ladder that is leaning against a vertical wall.
The ladder makes an angle of 30 degrees with the wall.
We need to find the work done by the gravity on the painter.
The angle between the weight of the painter and the displacement is :
θ = 180 - 30
= 150°
The work done by the gravity is given by :
Hence, the required work done is 1786.17 J.