Answer: Get stronger. Strength is critical to running fast because the more force you can exert against the ground the faster you can run.
Apply your new strength. Being strong is important for sprinting, but the ability to apply it is even more important. Sprinters move in a horizontal direction.
Take longer steps more quickly. Today, the concept of exerting more force against the ground is very popular for improving speed. ...
Run fast to get fast. Of all the strategies described in this article, this is the most important and often the most overlooked.
Explanation:
Answer:
option D
Explanation:
The correct answer is option D
Netnography is a set of research practice which is used in the collection of data, analysis of the data and representation of it. Most of the data is collected by a public conversation recorded by the communication network.
Netnography uses the conversation as collected data.
so, Photos shared on Instagram can be used to track consumption patterns and conversations of online consumers.
Answer:
Creatine is a great option , its not gonna help long term running ; but a great boost when you first start the run/jog.
Now to run faster you have to build great endurance and that is done through constant exercise running and stamina work outs such as sports , sprints calistetics etc.
Explanation:
Its not a simple 1 time thing and your suddenly , it takes drive and motivation !
Hope i was able to help you out ! Have a great day :)
Answer:
Explanation:
We shall take the help of vector form of displacement . Taking east as i and north as j
4.0m N = 4 j
7.5 m E = 7.5 i
6.8 m S = - 6.8 j
3.7 m E, = 3.7 i
3.6 m S = - 3.6 j
5.3 m W = - 5.3 i
3.7 m N, = 3.7 j
5.6 m W = - 5.6 i
4.4 m S = - 4.4 j
4.9 m W = - 4.9 i
Total displacement = 4j +7.5 i -6.8j+3.7i-3.6j-5.3i+3.7j-5.6i-4.4j-4.9i
= -4.6 i -7.1 j
magnitude of displacement = 
= 8.46 m
Direction
Tanθ = 7.1/ 4.6
θ = 57⁰ south of west .
distance walked = 4+7.5 +6.8+3.7+3.6+5.3+3.7+5.6+4.4+4.9
= 49.5 m
Explanation:
It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.
So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.
U = qV
Since, the electric potential is directly proportional to the charge. Hence, when 0.2 
tends to replaced by 0.4 then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.
Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.
