Compared to the charge on a proton, the amount of charge on an electron is same and has the opposite sign
Use acceleration = Final Velocity - Initial Velocity. So for the first one:
1.6m/s - 3.6m/s = -2.6m/s. This means the velocity changed by a negative amount so the acceleration is negative.
Answer:
Vf = 4.40 m/s and θ = 88º
Explanation:
To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.
Let's use trigonometry to break down the forces
Sin 25 = F1x / F1
Cos 25 = F1y / F1
Fix = F1 sin 25
F1x = 1.85 sin 25
F1x = 0.78 N
F1y = 1.85 cos 25
F1y = 1.67 N
F2 = - 0.782 N j ^ (south)
F3 = - 0.750 N i ^ (west)
We write Newton's second law
X axis (East-West)
F1x - F3 = m ax
ax = (F1x - F3) / m
ax = (0.78 - (0.750)) / 0.325
ax = 0.092 m / s²
Y axis (North-South)
F1y - F2 = m ay
ay = (1.67- (0.782)) / 0.325
ay = 2.73 m / s²
Let's calculate the magnitude and direction of the acceleration
a = RA ax2 + ay2
a = RA 0.092² + 2.73²
a = 2.73m / s²
tan θ = ay / ax
θ = tan⁻¹ (2.73/0.092)
θ = tan⁻¹ 29.67
θ = 88º
We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement
Vf² = vo² + 2 at D
Vf² = 0 + 2 2.73 3.55
Vf = √ 19.38
Vf = 4.40 m / s
θ = 88º
The correct answer is c because the other three is incorrect.
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Transparent means almost all the light passes through it, so D.