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3 years ago

Can you tell me what a substance is

Physics

2 answers:

VladimirAG [237]3 years ago

7 0

Answer:

Explanation:

a particular kind of matter with uniform properties.

LuckyWell [14K]3 years ago

6 0

Answer:

a particular kind of matter with uniform properties or the real physical matter of which a person or thing consists and which has a tangible, solid presence.

Explanation:

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Which of the following does NOT represent Newton’s second law? Question 20 options: a = m/Fnet m = Fnet/a Fnet = ma a = Fnet/m

Natali [406]

Answer:

a=m/f is not an equation under newton's second law

Explanation:

newton's second law of motion is represented using: f=ma

where a=v-u/t

therefore it becomes,f=m(v-u)/t

from f=ma,

a will become f/m,

m will become f/a

8 0

3 years ago

Car mass of 1167 kg accelerates on a flat highway from 10.0 m/s to 28.0 m/s. how much work does thr car's engine do on the car ?

jolli1 [7]

For the work-energy theorem, the work done by the engine on the car is equal to the variation of kinetic energy of the car:
$W= K_f-K_i=\frac{1}{2}mv_f^2 - \frac{1}{2} mv_i^2$
where m=1167 kg is the mass of the car, $v_i=10.0 m/s$ is the initial speed and $v_f=28.0 m/s$ is the final speed.

Putting numbers into the equation, we find:
$W= \frac{1}{2}(1176 kg)(28.0m/s)^2- \frac{1}{2}(1167 kg)(10.0 m/s)^2=4.0 \cdot 10^5 J$

6 0

4 years ago

PLEASE HELP!!!!!!!!Move on to electric force. Blow up the two balloons and knot them. Then tie a thread onto each balloon. Suspe

Triss [41]

Answer:

they attract

Explanation:

8 0

3 years ago

Read 2 more answers

In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary

Evgesh-ka [11]

Answer:

Explanation:

Given

initial height $h=2.5 m$

$m_2=2m_1$

coefficient of static friction $\mu =0.5$

When collision is elastic respective velocities after collision is

$v_1=\frac{u_1(m_1-m_2)+2m_2u_2}{m_1+m_2}$

$v_2=\frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2}$

where $u_1$ and $u_2$ =initial velocities of object

$v_1$ and $v_2$ final velocities of object

$u_1=\sqrt{2\times 9.8\times 2.5}$

$u_1=7 m/s$

$v_2=\frac{0+2m_1\times 7}{m_1+2m_1}$

$v_2=\frac{14}{3} m/s$

using $v^2-u^2=2 as$

$0-(4.67)^2=2\times (-0.5\times 9.8)\times s$

$s=2.22\ m$

(b)Completely Inelastic

In Completely Inelastic objects stick with each other

$m_1u_1=(m_1+m_2)v$

$v=\frac{u_1}{3}=\frac{7}{3} m/s$

using $v^2-u^2=2 as$

$0-(2.33)^2=2\times (-0.5\times 9.8)\times s$

$s=0.55\ m$

7 0

4 years ago

Why does your body feels like it is being pushed back when the car starts back up again

Llana [10]

The acceleration due to gravity is not due to the Earth's motion through space. It is due to the gravitational force pulling you towards the center of mass of the Earth. The ground pushes back, and what you feel is your weight. This is the same as what you feel in an accelerating car.

5 0

4 years ago