Springs in series will experience the same force all throughout and the elongation will add up. Springs in parallel will experience different forces and the elongation will be the same for each. The ranking will be from lowest to highest:
Case 3
Case 2
Case 1
Case 4
Case 5
since the car moves, the force needed to move is greater than the frictional forces opposing it
a = 3.17m/s²
Iron, cobalt, and nickel are elements with a magnetic field.
Explanation:
It is given that,
Density of asteroid, ![\rho=4000\ kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D4000%5C%20kg%2Fm%5E3)
Mass of asteroid, ![m=10^{17}\ kg](https://tex.z-dn.net/?f=m%3D10%5E%7B17%7D%5C%20kg)
We need to find the diameter of the asteroid. The formula of density is given by:
![\rho=\dfrac{m}{V}](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7Bm%7D%7BV%7D)
V is the volume of spherical shaped asteroid, ![V=\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
![r^3=\dfrac{3M}{4\pi \rho}](https://tex.z-dn.net/?f=r%5E3%3D%5Cdfrac%7B3M%7D%7B4%5Cpi%20%5Crho%7D)
![r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}](https://tex.z-dn.net/?f=r%5E3%3D%5Cdfrac%7B3%5Ctimes%2010%5E%7B17%7D%5C%20kg%7D%7B4%5Cpi%20%5Ctimes%204000%5C%20kg%2Fm%5E3%7D)
![r^3=\sqrt{5.96\times 10^{12}}](https://tex.z-dn.net/?f=r%5E3%3D%5Csqrt%7B5.96%5Ctimes%2010%5E%7B12%7D%7D)
r = 2441311.12 m
Diameter = 2 × radius
d = 4882622.24 m
or
![d=4.88\times 10^6\ m](https://tex.z-dn.net/?f=d%3D4.88%5Ctimes%2010%5E6%5C%20m)
Hence, this is the required solution.