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olya-2409 [2.1K]
4 years ago
9

A 50-kg cart is on an incline of 30 degrees above the horizontal. The cart is at rest. The static coecient of the slope is 0.85

and the kinetic coecient is 0.50. What is the force due to friction on the cart?
Physics
1 answer:
Tasya [4]4 years ago
6 0

Answer:

The force due to friction on the cart is 245 N.          

Explanation:

Given that,

Mass of the cart, m = 50 kg

It is placed on an incline of 30 degrees above the horizontal.

Initially, the cart is at rest.

The coefficient of static friction is 0.85 and the coefficient of kinetic friction is 0.5.

The net force acting along the horizontal direction is given by :

F=f-mg\sin \theta

Here, net force is 0.

f=mg\sin \theta\\\\f=50\times 9.8\times \sin (30)\\\\f=245\ N

So, the force due to friction on the cart is 245 N.                    

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