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natima [27]
3 years ago
10

Which best describes his run?

Physics
2 answers:
mezya [45]3 years ago
8 0
May I have a picture of the problem I need more information
Troyanec [42]3 years ago
4 0
Can you send a picture of the question or graph? There isn’t enough information here to answer
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Which statement best summarizes Newton's law of action-reaction? *
Tom [10]

Answer:

The correct answer is the third

Force equals mass times acceleration

Explanation:

Newton's second law says that force equals mass times the acceleration of the body

            F = m a

This is the most used way to solve problems

The correct answer is the third

Newton's third law states that forces always work in pairs, by action and reaction

Newton's first law states that an object per macerate with constant speed unless some force modifies this state.

4 0
3 years ago
Which tool would you use to measure the amount of rainfall?
zheka24 [161]

Answer:

a

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the wavelength associated with electrons moving with p.d of 1500v
Artist 52 [7]

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

4 0
3 years ago
the diagram shows changes of state between solid liquid and gas the atoms of a substance loses energy during a change of state a
Tpy6a [65]
Close together but are able to slide past one another
8 0
3 years ago
Read 2 more answers
g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosyn
krok68 [10]

Answer:

r = 4.21 10⁷ m

Explanation:

Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining

            T² = (\frac{4\pi }{G M_s} ) r³             (1)

           

in this case the period of the season is

            T₁ = 93 min (60 s / 1 min) = 5580 s

            r₁ = 410 + 6370 = 6780 km

            r₁ = 6.780 10⁶ m

for the satellite

           T₂ = 24 h (3600 s / 1h) = 86 400 s

if we substitute in equation 1

            T² = K r³

            K = T₁²/r₁³

            K = \frac{ 5580^2}{ (6.780 10^6)^2}

            K = 9.99 10⁻¹⁴ s² / m³

we can replace the satellite values

            r³ = T² / K

            r³ = 86400² / 9.99 10⁻¹⁴

            r = ∛(7.4724 10²²)

            r = 4.21 10⁷ m

this distance is from the center of the earth

7 0
3 years ago
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