A 12,500 kg railroad freight car travels on a level track at a speed of 5.2 m/s. It collides and couples with a 22,600 kg second
1 answer:
Given :
A 12,500 kg railroad freight car travels on a level track at a speed of 5.2 m/s.
It collides and couples with a 22,600 kg second car, initially at rest and with brakes released.
To Find :
The speed of the two cars after collision.
Solution :
It is given that car couples with each other. So speed of both the cars after collision is same. Let, it be v.
Applying conservation of momentum, we get :
Therefore, the speed of the two cars after collision is 1.85 m/s.
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Answer:
work output is always less than work input - the ratio is less than 1.
Explanation:
This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).
In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.
Regarding the ratio work output to work input:
because work input WI is always greater than work output WO.