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jonny [76]
3 years ago
8

On earth which of the following are being investigated to contain fusion reactions

Physics
2 answers:
gavmur [86]3 years ago
6 0

Answer:

<h2>Magnetic Confinement.</h2><h2>Inertial Confinement.</h2>

Explanation:

Magnetic Confinement Fusion is studied to generate thermonuclear energy through fusion power, using magnetic fields to transform matter into plasma.

On the other hand, Inertial Confinement Fusion is a type of research aimed to produce nuclear fusion reactions through heat and compression of a fuel.

These two researches comprehend the Fusion Energy Research, which is aimed to produce and develop plasma as a energy resource.

Vera_Pavlovna [14]3 years ago
3 0

Answer:

A. Inertial Confinement and B. Magnetic Confinement

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A ship maneuvers to within 2.46×10³ m of an island’s 1.80 × 10³ m high mountain peak and fires a projectile at an enemy ship 6.1
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The distance close to the peak is 597.4 m.

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Given that,

Distance of the first ship from the mountain d=2.46\times10^{3}\ m

Height of islandh=1.80\times10^{3}\ m

Distance of the enemy ship from the mountain d'=6.10\times10^{2}\ m

Initial velocity v=2.55\times10^{2}\ m/s

Angle = 74.9°

We need to calculate the horizontal component of initial velocity

Using formula of horizontal component

v_{x}=v\cos\theta

Put the value into the formula

v_{x}=2.55\times10^{2}\cos74.9

v_{x}=66.42\ m/s

We need to calculate the vertical component of initial velocity

Using formula of vertical component

v_{y}=v\sin\theta

Put the value into the formula

v_{y}=2.55\times10^{2}\sin74.9

v_{y}=246.19\ m/s

We need to calculate the time

Using formula of time

t=\dfrac{d}{v_{x}}

t=\dfrac{2.46\times10^{3}}{66.42}

t=37.03\ sec

We need to calculate the height of the shell on reaching the mountain

Using equation of motion

H= v_{y}t-\dfrac{1}{2}gt^2

Put the value in the equation

H=246.19\times37.03-\dfrac{1}{2}\times9.8\times(37.03)^2

H=2397.4\ m

We need to calculate the distance close to the peak

Using formula of distance

H'=H-h

Put the value into the formula

H'=2397.4-1800

H'=597.4\ m

Hence, The distance close to the peak is 597.4 m.

6 0
3 years ago
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