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jonny [76]
2 years ago
8

On earth which of the following are being investigated to contain fusion reactions

Physics
2 answers:
gavmur [86]2 years ago
6 0

Answer:

<h2>Magnetic Confinement.</h2><h2>Inertial Confinement.</h2>

Explanation:

Magnetic Confinement Fusion is studied to generate thermonuclear energy through fusion power, using magnetic fields to transform matter into plasma.

On the other hand, Inertial Confinement Fusion is a type of research aimed to produce nuclear fusion reactions through heat and compression of a fuel.

These two researches comprehend the Fusion Energy Research, which is aimed to produce and develop plasma as a energy resource.

Vera_Pavlovna [14]2 years ago
3 0

Answer:

A. Inertial Confinement and B. Magnetic Confinement

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10.0 ppm 10.4 ppm 10.2 ppm 10.8 ppm 10.1 ppm 10.5 ppm 10.1 ppm Using the new instrument on the first day the technicians got a v
iren [92.7K]

Answer:

The datapoint 9.0 ppm is outlier at the 90% confidence level.

Explanation:

The old data has following values

mean=10.5 mm

standard deviation 0.2 mm

Now the mean of new values is calculated as following

mean=\frac{10+10.4+10.2+10.8+10.1+10.5+10.1}{7}\\mean=10.3 ppm

So the value as 9.0 ppm can be considered easily as outlier in  this regard.

3 0
3 years ago
A 91.0-kg hockey player is skating on ice at 5.50 m/s. another hockey player of equal mass, moving at 8.1 m/s in the
never [62]

The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\rm  m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

8 0
2 years ago
A 0.500-kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the
Semenov [28]

Answer:

B. 7.07 m/s

Explanation:

The velocity of the stone when it leaves the circular path is its tangential velocity, v, which is given by

v=\omega r

where \omega is the angular speed and r is the radius of the circular path.

\omega is given by

\omega = 2\pi f

where f is the frequency of revolution.

Thus

v=2\pi fr

Using values from the question,

v=2\pi\times 1.50\times0.75

<em>Note the conversion of 75 cm to 0.75 m</em>

v=2\times3.14\times 1.50\times0.75 = 9.42\times0.75 = 7.065=7.07

6 0
3 years ago
Which is a characteristic of the atom marked A
erastovalidia [21]
Its very dense. Hey, are you homeschooled?
6 0
3 years ago
Which number is larger value : 5.6*10^23 or 8.9*10^6<br><br> Need Help
oee [108]

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

8 0
2 years ago
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