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xz_007 [3.2K]
3 years ago
6

A current carrying loop of width a and length b is placed near a current carrying wire. How does the net force on the loop compa

re to the net force on a single wire segment of length a carrying the same amount of current placed at the same distance from the wire
Physics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer/ Explanation

the loop has no force and the wires cancel each other but the wire on the loop has a force

The segment a get the same force for both but in the loop segment b get an opposite force so the net force on the loop is smaller

The loop wire has forces that all cancel out while the other straight wire doesn't.

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Jennifer and Katie are leaning on each other. Jennifer weighs 150 and Katie weighs 120. Which one is pushing harder on the other
murzikaleks [220]

Jennifer

Explanation:

she has more mass which means she is using more force

3 0
3 years ago
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A string that is restricted at both ends has a length of 1.50 m. what is the wavelength of the string’s fundamental frequency?
lara31 [8.8K]
Since it is restricted at both ends, λ/2 = length of string

λ/2 = 1.5m
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6 0
2 years ago
Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and throu
Serggg [28]

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose  = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges  

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,  

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

6 0
2 years ago
A 16 foot ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 3 feet per second, how fa
JulsSmile [24]

Answer:

11.625

Explanation:

L = length of the ladder = 16 ft

v_{y} = rate at which top of ladder slides down = - 3 ft/s

v_{x} = rate at which bottom of ladder slides

y = distance of the top of ladder from the ground

x = distance of bottom of ladder from wall = 4 ft

Using Pythagorean theorem

L² = x² + y²

16² = 4² + y²

y = 15.5 ft

Also using Pythagorean theorem

L² = x² + y²

Taking derivative both side relative to "t"

0 = 2x\frac{\mathrm{d} x}{\mathrm{d} t} + 2y\frac{\mathrm{d} y}{\mathrm{d} t}

0 = x v_{x} + y v_{y}

0 = 4 v_{x} + (15.5) (- 3)

v_{x} = 11.625 ft/s

7 0
3 years ago
My buddy and I have just finished a dive to 15 metres/50 feet for 60 minutes. We want to return to the same site and depth and s
marishachu [46]

Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

7 0
2 years ago
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