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xz_007 [3.2K]
3 years ago
6

A current carrying loop of width a and length b is placed near a current carrying wire. How does the net force on the loop compa

re to the net force on a single wire segment of length a carrying the same amount of current placed at the same distance from the wire
Physics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer/ Explanation

the loop has no force and the wires cancel each other but the wire on the loop has a force

The segment a get the same force for both but in the loop segment b get an opposite force so the net force on the loop is smaller

The loop wire has forces that all cancel out while the other straight wire doesn't.

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A

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3 years ago
You are comparing two diffraction gratings using two different lasers: a green laser and a red laser. You do these two experimen
Nikolay [14]

Answer:

a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center

Explanation:

Let  n₁ and n₂ be no of lines per unit length  of grating A and B respectively.

λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,

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= λ₁ D/ d₁

Distance of first maxima for red light

= λ₂ D/ d₂

Given that

λ₁ D/ d₁ = λ₂ D/ d₂

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d₁ < d₂

Therefore no of lines per unit length of grating A will be more because

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λ₁ D/ d₂ < λ₂ D/ d₂

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In this case position of first maxima will be less than 1 meter.

Option a is correct .

5 0
3 years ago
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