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xz_007 [3.2K]
4 years ago
6

A current carrying loop of width a and length b is placed near a current carrying wire. How does the net force on the loop compa

re to the net force on a single wire segment of length a carrying the same amount of current placed at the same distance from the wire
Physics
1 answer:
makvit [3.9K]4 years ago
5 0

Answer/ Explanation

the loop has no force and the wires cancel each other but the wire on the loop has a force

The segment a get the same force for both but in the loop segment b get an opposite force so the net force on the loop is smaller

The loop wire has forces that all cancel out while the other straight wire doesn't.

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A canister is filled with 310 g of ice and 100. G of liquid water, both at 0 ∘c . The canister is placed in an oven until all th
olya-2409 [2.1K]

Here in the process we require

1. Heat to melt down all ice

2. Heat to raise the temperature of whole water to 100 degree C

3. Heat to boil off the water

now here for the first part

Heat required to melt the ice

Q_1 = mL

Q_1 = 310*80  = 24800 cal

now heat required to raise the temperature to 100 degree C

Q_2 = ms\Delta T

Q_2 = (310 + 100)*1*(100 - 0)

Q_2 = 41000 cal

Now heat required to boil it off

Q_3 = mL

Q_3 = 410*540 = 221400 cal

now the total heat required will be

Q = Q_1 + Q_2 + Q_3

Q = 24800 + 41000 + 221400

Q = 287200 cal

so it required 287200 calorie heat to boil it all water

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3 years ago
Plzz helpppp meee!!!!
spin [16.1K]
A=f/m
A=900/425
A=2.18

To determine acceleration you divide the force by the mass.
4 0
3 years ago
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Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave
ehidna [41]

Answer:

A) P = 3.3 × 10^(-11) Pa

B) Amplitude of electric field = 1.931 N/C

Amplitude of magnetic field = 6.44 × 10^(-9) T

C) μ_av = 1.65 × 10^(-11) J/m³

D) 50% each for the electric and magnetic field

Explanation:

A) First of all let's calculate intensity.

I = P_av/A

We are given;

P_av = 777 KW = 777,000 W

Distance = 5 km = 5000 m

Thus;

I = 777000/(2π × 5000²)

I = 0.00495 W/m²

Now, the average pressure would be given by the formula;

P = 2I/C

Where C is speed of light = 3 × 10^(8) m/s

P = (2 × 0.00495)/(3 × 10^(8))

P = 3.3 × 10^(-11) Pa

B) Formula for the amplitude of the electric field is gotten from;

E_max = √[2I/(εo•c)].

Where εo is the Permittivity of free space with a constant value of 8.85 × 10^(−12) c²/N.mm²

I and c remain as before.

Thus;

E_max = √[(2 × 0.00495)/(8.85 × 10^(−12) × 3 × 10^(8))]

E_max = √3.72881355932

E_max = 1.931 N/C

Formula for amplitude of magnetic field is gotten from;

B_max = E_max/c

B_max = 1.931/(3 × 10^(8))

B_max = 6.44 × 10^(-9) T

C) Formula for average density is;

μ_av = εo(E_rms)²

Now, E_rms = E_max/√2

Thus;

E_rms = 1.931/√2

μ_av = 8.85 × 10^(−12) × (1.931/√2)²

μ_av = 1.65 × 10^(-11) J/m³

D) The energy density for the electric and magnetic field is the same. So both of them will have 50% of the energy density.

4 0
3 years ago
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kolbaska11 [484]

Answer:

they have given us

power = 900W

time = 30s

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4 0
3 years ago
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One's perception depends on the way the brain interprets the stimuli. true or false
bulgar [2K]
The answer is true .
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4 years ago
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