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lapo4ka [179]
3 years ago
14

If the amplitude of a wave is increased the frequency of the wave will

Physics
1 answer:
Travka [436]3 years ago
3 0

Answer:

Remain the same

Explanation:

There is no relationship between amplitude frequency.

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use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help ​
kati45 [8]

Answer:

L = 3.51

Explanation:

Pendulum equation is T = 2pi\sqrt{L/9.81}

T = 1.5 and we are solving for L

1.5=2\pi \sqrt{L/9.81}

square both sides to get 2.25 = 2\pi ( L/9.81)

multiply both sides by 9.81 then divide by 2 and 3.14 as a substitue for pi. The answer should be about 3.51 in length

L = 3.51

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3 years ago
Why is argon gas used instead of air in light bulbs that contain a filament that is heated to glowing?
tamaranim1 [39]
<span>the heated filament will react with the oxygen in the air but now with the argon, which is a noble gas and hardly ever reacts.</span>
3 0
3 years ago
T or f :static electricity constantly flows in the same direction
Kazeer [188]

Answer:

False

because I got that question and I gotted right

6 0
3 years ago
A cinder cone is formed from relatively ________ viscosity magma with a ________ gas content. low; high high; high low; low high
kenny6666 [7]

<span>A cinder cone is formed from relatively low viscosity magma with a high gas content. Cinder cones are formed by the volcanic ash, cinders that are formed around the volcanic vent. Cinder cones have a bowl shaped crater and the shape of the cinder cones depend on the ejected particles that formed the cinder.</span>

5 0
3 years ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
beks73 [17]

Answer:

4.6 kHz

Explanation:

The formula for the Doppler effect allows us to find the frequency of the reflected wave:

f'=(\frac{v}{v-v_s})f

where

f is the original frequency of the sound

v is the speed of sound

vs is the speed of the wave source

In this problem, we have

f = 41.2 kHz

v = 330 m/s

vs = 33.0 m/s

Therefore, if we substitute in the equation we find the frequency of the reflected wave:

f'=(\frac{330 m/s}{330 m/s-33.0 m/s})(41.2 kHz)=45.8 kHz

And the frequency of the beats is equal to the difference between the frequency of the reflected wave and the original frequency:

f_B = |f'-f|=|45.8 kHz-41.2 kHz|=4.6 kHz

6 0
3 years ago
Read 2 more answers
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