2 years ago

Stages of global warming

Physics

1 answer:

ddd [48]2 years ago

7 0

Answer:

- Glaciers melt

- The seas rise

- Temperature changes

- Humans add heat trapping greenhouse gasses

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150

Sever21 [200]

Answer: $2.89\approx 2.9^{\circ}C/s$

Explanation:

Given

$Power\left ( P\right )=150 MW$

mass of core $\left ( m\right )=1.60\times 10^5 kg$

Average specific heat $\left ( C\right )=0.3349 KJ/kg^{\circ}C$

And rate of increase of temperature = $\frac{\mathrm{d}T}{\mathrm{d} t}$

Now

P= $mc\frac{\mathrm{d}T}{\mathrm{d} t}$

$150\times 10^6=1.60\times 10^5\times 0.3349\times \frac{\mathrm{d}T}{\mathrm{d} t}$

Thus $\frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}$

$\frac{\mathrm{d}T}{\mathrm{d} t}=2.89\approx 2.9^{\circ}C/s$

6 0

3 years ago

If it takes you 10 seconds to move a chair 5 meters across the floor, using a force of 2 Newtons, how much power did you put out

Maru [420]

Answer:

power=work done÷time taken

2×5=10

10÷10=1

ans 1J per second

5 0

1 year ago

Explain how the data collected and the calculations for the first and second resonance points in today's experiment would change

grandymaker [24]

Answer:

tssths

Explanation:

hgst

8 0

2 years ago

A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?

Montano1993 [528]

As we know,

$electric \: \: current = \dfrac{charge}{time}$

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

$0.2 = \dfrac{q}{300}$

$q = 300 \times 0.2$

$q = 60$

hence, the charge = 60 coulombs (C)

4 0

2 years ago

Calcular la rapidez promedio

Vlada [557]

Answer:

v_average = 15 m / s

Explanation:

The average speed can be found in two ways,

* taking the distance traveled and divide it by the time spent

* taking the velocities in each time interval and then finding the weighted average by the time fraction

v_average = 1 / t_total ∑ $v_{i} t_{i}$ vi ti

Let's apply this last equation

Total time is

t = t₁ + t₂

t = 10 + 10 = 20 min

v_average = 10/20 10 + 10/20 20

v_average = 10/2 + 20/2

v_average = 15 m / s

7 0

2 years ago