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Mashutka [201]
3 years ago
9

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 49 m in front of you. You reaction time

before stepping on the brakes is 0.50 s, and the maximum deceleration of your car is 10m/s2.
a. How much distance is between you and the deer when you come to a stop?
b. What is the maximum speed you could have and still not hit the deer?
Physics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

v = 26.7 m/s

Explanation:

Given,

speed of the car = 20 m/s

distance between the car and the deer = 49 m

time taken to press the brake = 0.50 s

maximum deceleration of the car = 10 m/s²

Now,

distance travel by the car in 0.5 s = u x t = 20 x 0.5 = 10 m

distance travel by the car after the break is pressed

Using equation of motion

v² = u² + 2 a s

0² = 20² - 2 x 10 x s

s = 20 m

Total distance travel by the car = 20 + 10 = 30 m

Distance between deer and car = 49-30 = 19 m.

b. Maximum speed a car could have

Distance travel by the car in reaction time = v' x 0.5

v' is the maximum speed of the car.

maximum distance car can cover = 49 - 0.5 v'

Now, Using equation of motion

v² = u² + 2 a s

0² =v'² - 2 x 10 x (49- 0.5 x v')

v'² +10 v' -980 = 0

By solving

v = 26.7 m/s

Hence, maximum speed of the car can be 26.7 m/s

 

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Answer:

-2.79 m/s²

Explanation:

Given:

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v = 11 m/s

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Find: a

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(11 m/s)² = (20 m/s)² + 2a (50 m)

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Answer:

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Explanation:

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A motion security line is a system that is used to detect motion.
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