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3 years ago

-Subtract and simplify -y^2-3y-5)-(x36^2-7y+4

Mathematics

1 answer:

AnnZ [28]3 years ago

5 0

Answer:

-y^2 - 10 y - x^72 + -1

Step-by-step explanation:

Simplify the following:

-y^2 - 3 y - 5 - (x^36)^2 - 7 y + 4

Multiply exponents. (x^36)^2 = x^(36×2):

-y^2 - 3 y - 5 - x^(36×2) - 7 y + 4

36×2 = 72:

-y^2 - 3 y - 5 - x^72 - 7 y + 4

Grouping like terms, -y^2 - 3 y - 5 - x^72 - 7 y + 4 = -y^2 + (-3 y - 7 y) - x^72 + (4 - 5):

-y^2 + (-3 y - 7 y) - x^72 + (4 - 5)

-3 y - 7 y = -10 y:

-y^2 + -10 y - x^72 + (4 - 5)

4 - 5 = -1:

Answer: -y^2 - 10 y - x^72 + -1

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