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3 years ago

The diagram shows a triangle. 20s 20s 20s What is the value of s?

Mathematics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer: I’m assuming that these are Angle measures. S=3

Step-by-step explanation:

180/3=60

20*3=60

S=3

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If 6x + 5y = 10, what is y in terms of x?<br> Please include an explanation!

Mnenie [13.5K]

what you're trying to do is form an equation for y

6x + 5y = 10

5y = -6x + 10 we need y to be singular so divide by numeral before y

y = - 6x/5 + 10/5

y = - 6x/5 + 2

6 0

2 years ago

Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0

3 years ago

One batch of cookies calls for 2 cups of oil, 4 cups of sugar, 1.5 cups of sugar, 1 cup of baking soda, and 1 cup of chocolate c

hichkok12 [17]

He can make 2 batches of cookies. I'm not sure about the leftover cups because you wrote sugar twice

4 0

3 years ago

Solve 765/14 and write your answer in terms of a mixed number (please use this format: 75 3/5). *

kozerog [31]

the answer is 54 9/14

because Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

6 0

3 years ago

Read 2 more answers

Second pictures of my last question

Elanso [62]

Answer:

you really did not give us the full pictuer

Step-by-step explanation:

8 0

2 years ago