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3 years ago

Kite QRST has sides RS, ST, TQ and QR. What are the diagonals of this figure? Select all that apply.

Mathematics

2 answers:

Rina8888 [55]3 years ago

8 0

The diagonals are QS and RT

Sav [38]3 years ago

7 0

We have that Q is adjacent to T and R since we have that the edges of the kite include TQ and QR. Thus it is opposite of S and we have that one diagonal is SQ. By now we know that the other diagonal must be TR but let us verify it. T is adjacent to S and Q by the same reasoning, so the only vertex that is opposite is R. Hence, the other diagonal is TR.

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What is the range of the relation below?

Ilya [14]

Answer:

Step-by-step explanation:

I had the same question

7 0

2 years ago

A sample has a sample proportion of 0.3. which sample size will produce the

jasenka [17]

The sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.

<h3>What are population and sample?</h3>

It is described as a collection of data with the same entity that is linked to a problem. The sample is a subset of the population, yet it is still a part of it.

We have:

A sample has a sample proportion of 0.3.

Level of confidence = 95%

At the same confidence level, the larger the sample size, the narrower the confidence interval.

As we have a 95% confidence interval the sample size should be lower.

The sample size from the option = 36 (lower value)

Thus, the sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.

Learn more about the population and sample here:

brainly.com/question/9295991

#SPJ1

7 0

1 year ago

I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

4 0

3 years ago

Need help with this please

lana [24]

Answer:n

geadeeeeeeeeeee

Step-by-step explanation:

4 0

2 years ago

Suppose the average yearly salary of an individual whose final degree is a masters is $46 thousand less than twice that of an in

zepelin [54]

Answer:

average yearly salary of an individual whose final degree is a masters: $ 66 thousand

average yearly salary of an individual whose final degree is a bachelors: $ 56 thousand

Explanation:

You can set a system of equation using the following steps:

1. Name the variables:

average yearly salary of an individual whose final degree is a masters: x

average yearly salary of an individual whose final degree is a bachelors: y

2. Set the equations that relate the variables:

the average yearly salary of an individual whose final degree is a masters is $46 thousand less than twice that of an individual whose final degree is a bachelors:

equation (1): x = 2y - 46

combined, two people with each of these educational attainments earn $122 thousand:

equation (2): x + y = 122

3. Solve the system:

x = 2y - 46 . . . equation (1)

x + y = 122 . . . equation (2)

Substitute equation (1) into equation (2)

2y - 46 + y = 122

Solve for y:

3y = 122 + 46

3y = 168

y = 168 / 3

y = 56 (this means that the average yearly salary with a bachelors degree is $ 56 thousand).

Subsitute the value on y in equation 1, to find the value of x:

x = 2y - 46 = 2(56) - 46 = 112 - 46 = 66.

Thus, the average yearly salary of a person with a masters degree is $ 66 thousand.

4 0

3 years ago