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Alenkinab [10]
3 years ago
5

Please help with this question.

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
The answer is the top option.
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Suppose five people are in a room. What is the probability that there is at least one shared birthday among these five people?
iris [78.8K]

I think it would be 73

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What is the reciprocal of 9/14
KATRIN_1 [288]
14/9 because u just flip it to cancel it out
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Evaluate g (c) = 4 - 3x when c = -3, 0, and 5
Lana71 [14]

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6.09

Step-by-step explanation:

multiplayer ok so that is how I did it ok

6 0
3 years ago
Given that (5,-8) is on the graph of f(x), find
My name is Ann [436]

Answer:

The corresponding point for the function  f(x + 2) is (3 , -8)

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) translated horizontally to the right  by h units,

 then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  by h units,

 then the new function g(x) = f(x + h)

* Lets solve the problem

- There is a graph of f(x)

- Point (5 , -8) lies on the graph of f(x)

- The graph of f(x) change to f(x + 2)

∵ f(x) ⇒ f(x + 2)

∵ If the function f(x) translated horizontally to the left  by h units,

  then the new function g(x) = f(x + h)

∴ f(x) translated horizontally 2 units to the left

∴ Any point on the graph its x-coordinate translated 2 units

  to the left

∴ The x-coordinate of any point on the graph is subtracted by 2

∵ Point (5 , -8) lies on the graph

∴ Its corresponding point is (5 - 2 , -8) = (3 , -8)

* The corresponding point for the function  f(x + 2) is (3 , -8)

7 0
3 years ago
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
3 years ago
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