Which product of the ultraviolet decomposition of cfcs acts as the catalyst for ozone decomposition?

1 answer:

8 0

The answer is <span>Chlorine atoms. This is the </span><span>product of the ultraviolet decomposition of cfcs acts as the catalyst for ozone decomposition. </span>

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Theoretically, how many moles of carbonic acid will be produced by 3.00 g sample of NaHCO3?

Kryger [21]

NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27%

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3

0.8211 grams Na + 1.266 grams Cl = 2.087 grams

7 0

3 years ago

A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu

Yuki888 [10]

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K$

Putting values in above equation, we get:

$\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1$

Hence, the new pressure is 7.1 atm

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3 years ago

A rectangle solid of unknown density is 5 m long two meters high and 4 meters wide. The mass of this solid is 300 grams. Find th

aksik [14]

D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3

6 0

3 years ago

the density of aluminum is 2.70g/cm^3. a piece of aluminum foil has a volume of 54.0 cm^3. what is the mass of this piece of alu

Neporo4naja [7]

The mass of aluminium foil is calculated as follows
mass = density x volume
density = 2.70 g/cm^3
volume 54 cm^3
mass of aluminium foil is therefore = 2.70 g/cm^3 x 54 cm^3 =145.8 grams
cm^3 cancel out each other

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3 years ago

Explain how materials are classified on the basis of electrical conductivity. Give two uses of these materials in day to day lif

vitfil [10]

Answer: On the basis of electrical conductivity, materials are classified as conductors, semi-conductors and non-conductors. Conductors : Substances through which electricity can easily pass through are known as conductors. ... For example, glass, wood are non-conductors. Wood is used to make tables, desks etc.

3 0

2 years ago