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const2013 [10]
3 years ago
10

In a heating curve, when is the temperature constant? need answers!

Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
3 0
During a phase change
Bingel [31]3 years ago
3 0

<u>Answer: </u>The correct answer is Option 1.

<u>Explanation:</u>

For the given options:

<u>Option 1:</u> During a phase change

Whenever phase change occurs, the temperature remains constant because the heat is used to overcome the intermolecular forces between the particles.

<u>Option 2:</u> During a pressure change

As we know pressure is directly related to the temperature. So, if the pressure is increased, the temperature will also increase and vice-versa.

<u>Option 3:</u> During a change in kinetic energy

Kinetic energy is directly related to the temperature of a substance. So, if the kinetic energy is increased, the temperature will also increase and vice-versa.

<u>Option 4:</u> During a change in molecular velocity

Molecular velocity is directly related to the temperature of a substance. So, if the molecular velocity is increased, the temperature will also increase and vice-versa.

Hence, the correct answer is Option 1.

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The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
3 years ago
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Answer:

The answer is agriculture.

Explanation:

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Matter can be measured in many ways for specific purposes which measurement depends on the force of gravity and is not a reliabl
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Answer:True But matter can take up much space and is stronger than  density and gravity

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What is the general trend for electron affinity values going across a period? The
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Answer: The values become more negative

Explanation: I just took the quiz and got it correct :)

5 0
3 years ago
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You place 12.0 milliliters of water in a graduated cylinder. Then you add 15.0 grams of metal to the water and the new water lev
Marrrta [24]

Answer:

<h3>The answer is 7.85 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

volume = final volume of water - initial volume of water

volume = 13.91 - 12 = 1.91 mL

We have

density =  \frac{15}{1.91}  \\  = 7.853403141...

We have the final answer as

<h3>7.85 g/mL</h3>

Hope this helps you

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