1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lostsunrise [7]
3 years ago
15

A sled is pushed to right with a force of 200 N. The force of friction opposing that motion is 50 N. a) What is the Net Force on

the sled? b) assuming the mass of the sled is 30 kg, use Newton's 2nd Law equation to determine the acceleration. Include units in BOTH of your answers! *
Physics
1 answer:
marin [14]3 years ago
4 0

Answer:

Fr = 150 [N]

a = 5 [m/s²]

Explanation:

In order to find the resulting force, we must assume that the thrust force is positive to the right, while the friction force is negative to the left.

F_{r}=200-50\\F_{r}=150[N]

Now Newton's Second Law tells us that the sum of the forces or the resulting force is equal to the product of mass by acceleration.

F = m*a

150 = 30*a\\a=150/30\\a = 5 [m/s^{2} ]

You might be interested in
An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction
DiKsa [7]
Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
       = m(u/2)²
       = (1/4)mu²
      = (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer:  1/2 

5 0
4 years ago
Read 2 more answers
When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Sindrei [870]

Answer:

<h2> 0.041kg</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

m=0.04kg

The mass of the ball is 0.041kg

6 0
3 years ago
Pleaseeeee help me with b, c, and d. There are no angles.
taurus [48]

Answer:

a. 150 J

b. 150 J

c. 0 J

d. 0 J

Explanation:

The given parameters are;

The horizontal force with which the man pulls the canister, F = 50 N

The distance he moves the vacuum cleaner, d = 3.0 m

a. Work done, W = Force applied, F × Distance moved by the force, d

Therefore, for the work done by the 50 N force on the canister, we have;

W = 50 N × 3.0 m = 150 N·m = 150 J

b. Given that he pulls the canister at a constant speed, we have;

The acceleration of the canister, a = 0 m/s²

Therefore, the net force on the canister, F_{NET} = F - F_{Friction}  = m × a

Where;

m = The mass of the canister

a = The acceleration of the canister

F = The applied force = 50 N

F_{Friction} = The force of friction

∴ F_{NET} = m × a = m × 0 m/s² = 0 N

Therefore;

F_{NET} =  F - F_{Friction} = 0 N

From which we have;

F = F_{Friction} = 50 N (The applied force, F is equal to the force of friction,

The work done by friction = The force of friction × The distance in which the force of friction acts

∴ The work done by friction = F_{Friction} × d - 50 N × 3.0 m = 150 J

The work done by friction = 150 J

c. The normal force, N acts perpendicular to the force of friction

The distance the canister moves in the perpendicular direction, d_p = 0 m

∴ The work done by the normal direction = N × d_p = N × 0 m = 0 J

The work done by the normal direction = 0 J

d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N

Therefore, the weight, W, acts perpendicular to the line of motion of canister

The distance the canister moves in the direction of the weight, d_{wieght} = 0 m

Therefore, the work done by the weight = W × d_{wieght} = W × 0 m = 0 J

The work done by the weight = 0 J

7 0
3 years ago
On a planet with different gravity, would the molarity of water be different? explain your reasoning.
ruslelena [56]

On a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.

<h3>How to explain the gravity?</h3>

Although sunlight is the energy source, gravity is the main factor driving the water cycle. The Earth's gravity pulls matter downward and toward its center. Gravity is the force that attracts two objects. It pushes water downhill and precipitation from the clouds. Air and ocean water are also moved by gravity.

We understand that even if the gravitational pull varies throughout the universe, the molarity of water would be constant everywhere. This is thus because a substance's mass is unaffected by gravity; only its weight is. The quantity (or mass, indirectly) of a solute is used to calculate the molarity.

Here, on a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.

Learn more about gravity on:

brainly.com/question/557206

#SPJ1

5 0
1 year ago
Each of 100 identical blocks siting on a frictionless surface is connected to the next bloc by a massless string. The first bloc
Anit [1.1K]

Answer:

A) 1 N

B) 50 N

Explanation:

Let us consider that the string does not deform.

To solve this problem lets consider the whole system as two parts. In the initial case, the first part will be de 100N being exterted to the whole system and in the second the 100 blocks system.

In this case we can imagine as the whole system being pulled by 100 N, and therefore its acceleration will be:

a = 100 N /(100 m)

where m stantds for the mass of one block

Now, the whole system and its individual parts must move with the same acceleration otherwise the string would stretch.

Now lets consider the first part of the system as the first block, and the second part as the other 99 blocks.

The Tension of the string pulling the 99 blocks must be so that it exterts the enough force to move that 99blocks-system at an acceleration a, since that sub-system has a mass of 99m

T1 = 99 m * a = (99 m) * (100 N/ 100 m) = 99 N

Now lets consider an intermidiate sub-system, where the first part is made of n blocks and the second susbsystem is made of (100 -n) blocks

Following the same logic, the tension of the corresponding string must be the acceleration of the whole systems times the mass of the second subsystem:

Tn = (100 -n)m * ( 100 N / 100 m ) = (100 -n) N

a)

Therefore the tension in the string connecting block 100 to block 99 must be

<u>T99 = 1 N</u>

<u />

b)

And

<u>T50 = 50 N</u>

6 0
3 years ago
Other questions:
  • What is the frequency corresponding to a period of 4.31 s? answer in units of hz?
    12·1 answer
  • For a wave, what term is defined as the maximum height of a crest, or depth of a trough, relative to the normal level? for a wav
    15·1 answer
  • The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect, if any, does this have o
    6·1 answer
  • When a muscle contracts, it performs work. It does this by
    11·1 answer
  • Help with these questions
    5·1 answer
  • How are all the spheres similar
    15·1 answer
  • A bicyclist at the top of a hit begins to coast without pedaling. The bicycle speeds up as it descends to the bottom of the hill
    9·1 answer
  • Find the acceleration a body whose velocity increases from 11m/s to 33m/s in 10 seconds
    7·1 answer
  • A certain CD has a playing time of 74.0 minutes. When the music starts, the CD is rotating at an angular speed of 480 revolution
    14·1 answer
  • A first year student projected a farm business brochure to a farmer at 30 degrees to horizontal. calculate the maximum height at
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!