Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission,
million ponds/day
Standard deviation,
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:


= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:



P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Answer:
D. - 1/6
Step-by-step explanation:
M + 2/3 = 1/2
M = 1/2 - 2/3

P=s1+s2+s3
Move +s1 to the other side. Sign changes from +s1 to -s1
P-s1=s1-s1+s2+s3
p-s1=s2+s3
Move s2 to the other side. Sign changes from s2 to -s2
p-s1-s2=s2-s2+s3
p-s1-s2=s3
Answer: p-s1-s2=s3
Answer:
L = 100
W = 60
Step-by-step explanation:
2L + 2W = 320
-2L + 2W = -80
4W = 240
W = 60
L - W = 40
L - 60 = 40
L = 100