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natta225 [31]
3 years ago
8

A chamber fitted with a piston can be controlled to keep the pressure in the chamber constant as the piston moves up and down to

increase or decrease the chamber volume. The chamber contains an ideal gas at 296 K and 1.00 atm. What is the work done on the gas as the piston compresses it from 1.00 L to 0.633 L
Physics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

The work done on the gas is 37 J.

Explanation:

let P be the pressure in the chamber.

let V1 be the initial volume of the chamber.

let V2 be the final volume of the chamber.

then, the work done on the gas is given by:

W = P(V2 - V1)

    = (1×10^5)(1 - 0.633)×10^-3

    = 37 J

Therefore, the work done on the gas is 37 J.

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Readme [11.4K]
Hey there!

Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.

Your correct answer would be . . . 

</span>\boxed{\boxed{Every \ mass \ exerts \ a \ gravitational \ force \ on \ every \ other \ mass}}
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3 years ago
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a 0.15 kg baseball has a momentum of 0.78 kg*m/s just before it lands on the ground. What was the ball's speed just before landi
vovangra [49]

5.2m/s

Explanation:

Given parameters:

Mass of baseball = 0.15kg

Momentum of baseball = 0.78kgm/s

Unknown:

Speed of baseball = ?

Solution:

The momentum of the baseball is a function of the product of the mass and velocity. It is a vector quantity:

        Momentum = mass x velocity

 Since the speed of the ball is unknown:

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                           = \frac{0.78}{0.15}

                           = 5.2m/s

The speed of the baseball before it lands is 5.2m/s

Learn more:

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4 0
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The circuit below contains an ideal battery, four identical light bulbs, and a switch. The switch is initially open.
Dafna1 [17]

The question is incomplete! circuit figure is attached below and answer and explanation is provided below.

Answer:

Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.

Explanation:

What happens when switch is open?

When the switch is open Bulb_C is open circuited meaning that there is no way for the current to flow through it. This path offers infinite resistance to the current therefore, current will try to take a least resistance path that is through Bulb_B.

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What happens in a series circuit?

We know that in a series circuit, there is only one path for the current to flow therefore, same current will flow through all the series Bulbs and their brightness will be same. Bulb_A = Bulb_B = Bulb_D

Brightness in a series circuit:

We also know know that in a series circuit, resistance gets summed up and voltage across each Bulb gets shared which results in less power dissipation that's why Bulbs connected in series appear dimmer as compared to when they are connected in parallel.

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