A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 20.0 m/s. Then the truck trav
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Answer:
The magnitud of the velocity is
and the direccion:
degrees from the horizontal.
Explanation:
Fist we define our variables:
The letters i and j represent the direction of the movement, i in this case is the horizontal direction, and j is perpendicular to i.
velocities with sub-index 1 are the speeds before the crash, and with sub-index 2 are the velocities after the crash.
Using conservation of momentum:
Clearing for the velocity of the stone after the crash:
Substituting known values:
The magnitud of the velocity is :
and the direction:
this is -28.3 degrees from the +i direction or the horizontal direcction.
Note: i and j can also be seen as x and y axis.
To solve this problem, apply the concepts related to the centripetal acceleration as the equivalent of gravity, and the kinematic equations of linear motion that will relate the speed, the distance traveled and the period of the body to meet the needs given in the problem. Centripetal acceleration is defined as,
Here,
v = Tangential Velocity
r = Radius
If we rearrange the equation to get the velocity we have,
But at this case the centripetal acceleration must be equal to the gravitational at the Earth, then
The perimeter of the cylinder would be given by,
Therefore now related by kinematic equations of linear motion the speed with the distance traveled and the time we will have to
Therefore the period will be 44.9s