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Specific heat of the material thus calculated is 0.22 J/ g °C
<u>Explanation</u>:
Given:
Mass of the sample (m) = 50g
Heat energy = Q = 660 J
Temperature get raised from 20° C to 80° C
To Find:
Specific Heat of the material.
Formula to be used:
Q = m×C×ΔT
where we know that,
Heat energy = Q = 660 J
Mass = m = 50 g
ΔT = 80 - 20 = 60° C
Now to calculate the specific heat of the material (c) we must substitute all the values, Then we get,
Thus the Specific heat of the material is 0.22 J/ g °C.