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Lapatulllka [165]
3 years ago
8

The first mechanized industry was

Physics
1 answer:
Oxana [17]3 years ago
3 0
C. Textiles

It was the first thing mechanized in the Industrial Revolution

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A polo player hits a ball with a mass of 0.42 kg with a force of 7.35 Newtons.
Serga [27]
Due to the law of conservation of momentum, the force exerted on the mallet is equal and opposite to the force exerted on the ball, so the answer is C.
4 0
3 years ago
Read 2 more answers
a peice of titanium metal has a mass of 67.5 gm and a volume of 15 cm cubed. what is the density od titanium?​
Nuetrik [128]

density=mass/volume

mass=67.5

volume=15cm cube

so

67.5/15

4.5g/cm cube

6 0
3 years ago
Read 2 more answers
Which requires more work, increasing a car's speed from 0 mph to 30 mph or from 50 mph to 60 mph?
Gnom [1K]

Increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

<h3>What is work?</h3>

Work is a measure of energy expended in moving an object. It is calculated by multiplying the force by the distance.

According to this question, work is required to move a car from one position to another.

The distance moved from 0 - 30mph is more than that moved from 50 - 60mph, therefore, increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

Learn more about work at: brainly.com/question/19382352

#SPJ1

8 0
1 year ago
A 2 200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.20 m before coming into contact
77julia77 [94]

Answer:

F = 6.10 \times 10^5 N

Explanation:

Here we know that pile will go down under gravity for d = 4.20 m before coming in contact with beam

Now after being in contact with the beam the pile further go down by L = 15.4 cm.

Finally it will come to rest.

So here we can say that work done by gravity + work done by beam on the pile must be equal to change in its kinetic energy

So here we have

mg(L + d) - F(L) = 0

F = \frac{mg(L + d)}{L}

F = \frac{2200\times 9.81(4.20 + 0.154)}{0.154}

F = 6.10 \times 10^5 N

8 0
3 years ago
If the length of the rod is 2.65 m, and the mass of the bob and the rod are both 1.4 kg, what is the period of this pendulum
marusya05 [52]

Answer:

  T = 5.66 s

Explanation:

The system formed by the bar plus ball forms a physical pendulum

        w = \sqrt{mgd/I}

the moment of inertia of a rod held at one end is

       I = \frac{1}{3} m L²

we substitute

       w = \sqrt{\frac{d \ d}{ 3 L^2 } }

in this case the turning distance and the length of the rod are equal

        d = L

        w = \sqrt{\frac{g}{3L} }

angular velocity and period are related

       w = 2π / T

        2π / T = \sqrt{\frac{g}{3L} }

        T = 2π \sqrt{3L/g}

let's calculate

       T = 2π \sqrt{3 \ 2.65 / 9.8}

       T = 5.66 s

5 0
2 years ago
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