Answer:
x = y
Step-by-step explanation:
x/3 + x/6 = 7/2
2x + x = 21
3x = 21
(divide 3 on both sides)
x = 7
A line in the horizon meaning a straigh flat line, its counterpart is a vertical line which is up and down. If you look at an x/y line, the x line is the horizon line
2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:
1.50S + 2.50P > 20
Step-by-step explanation:
An inverse function is a function that reverses another function, so we have a function called:

Then, the inverse function will be as follows:

Given that

, we need to isolate x in terms of y:

∴

So:

and

therefore, exchanging variables x and y:

and


and

Which are the figures shown below.