D+n=25 subtract d from both sides *(if your wondering what d and n are it stands for Dimes and Nickels)* n=25-d
0.10d+0.05= 1.85
0.10d+0.05(25-d)= 1.85
0.10d+1.25-0.05d= 1.85
0.05d = 0.60
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My answer: He has 12 dimes (d=12) and 25-12=13 so 13 nickels.. Hope this helps! :)
Answer:
505.4 in²
Step-by-step explanation:
½d2= 19×tan 35° = 19×0.7 = 13.3 in
d2 = 2×13.3 = 26.6 in
d1 = 2×19=38 in
the area of Rhombus =
½×38×26.6 = 505.4 in²
The answer is "C", "MW".
In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
−3b+2.5=4
Subtract 2.5 from both sides.
−3b+2.5−2.5=4−2.5
−3b=1.5
Divide both sides by -3.
−3b/−3 = 1.5/−3
b=−0.5
